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| Started by | Richard Heathfield <rjh@cpax.org.uk> |
|---|---|
| First post | 2023-01-26 21:00 +0000 |
| Last post | 2023-03-01 11:59 -0800 |
| Articles | 2 — 2 participants |
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Re: Paragraph Wrapping Richard Heathfield <rjh@cpax.org.uk> - 2023-01-26 21:00 +0000
Re: Paragraph Wrapping Ezimene nimi Teine nimi <ezimenenimiteinenimi@gmail.com> - 2023-03-01 11:59 -0800
| From | Richard Heathfield <rjh@cpax.org.uk> |
|---|---|
| Date | 2023-01-26 21:00 +0000 |
| Subject | Re: Paragraph Wrapping |
| Message-ID | <tquplb$1a9o0$1@dont-email.me> |
On 26/01/2023 7:50 pm, Stefan Ram wrote: > The same book also gave another problem that could supposedly be > solved using dynamic programming: In a restaurant you are shown > five dishes in a sequence, and you can choose one to eat. You are > shown only one dish at a time and do not know which dish will be > shown next. Once you accept or reject a dish, you cannot go back on > your decision. If you do not choose any of the first four dishes, > this means that you would inevitably eat the last one. How should > you proceed to maximize the probability of getting the best dish? > > The solution given in the book begins by explaining that you > assign a quality score between 0 and 1 to each dish you see. > So the question is how to proceed to maximize the probability > of eating a dish with a quality score as high as possible . . . 0123456789 spoiler space 0123456789 spoiler spac 0123456789 spoiler spa 0123456789 spoiler sp 0123456789 spoiler s 0123456789 spoiler 0123456789 spoiler 0123456789 spoile 0123456789 spoil 0123456789 spoi 0123456789 spo 0123456789 sp 0123456789 s 0123456789 0123456789 012345678 01234567 0123456 012345 01234 0123 012 01 Reject (but score) the first two dishes, and then accept the first dish that scores better than any you have yet seen (or the last if you must and are very hungry). This algorithm will pick the best of five dishes about seven times in twenty visits. -- Richard Heathfield Email: rjh at cpax dot org dot uk "Usenet is a strange place" - dmr 29 July 1999 Sig line 4 vacant - apply within
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| From | Ezimene nimi Teine nimi <ezimenenimiteinenimi@gmail.com> |
|---|---|
| Date | 2023-03-01 11:59 -0800 |
| Message-ID | <d070c6dd-f9ea-4df3-bc85-6098117a7d41n@googlegroups.com> |
| In reply to | #16350 |
Good day, lord. On Thursday, January 26, 2023 at 11:00:35 PM UTC+2, Richard Heathfield wrote: > On 26/01/2023 7:50 pm, Stefan Ram wrote: > > The same book also gave another problem that could supposedly be > > solved using dynamic programming: In a restaurant you are shown > > five dishes in a sequence, and you can choose one to eat. You are > > shown only one dish at a time and do not know which dish will be > > shown next. Once you accept or reject a dish, you cannot go back on > > your decision. If you do not choose any of the first four dishes, > > this means that you would inevitably eat the last one. How should > > you proceed to maximize the probability of getting the best dish? > > > > The solution given in the book begins by explaining that you > > assign a quality score between 0 and 1 to each dish you see. > > So the question is how to proceed to maximize the probability > > of eating a dish with a quality score as high as possible . . . > > 0123456789 spoiler space > 0123456789 spoiler spac > 0123456789 spoiler spa > 0123456789 spoiler sp > 0123456789 spoiler s > 0123456789 spoiler > 0123456789 spoiler > 0123456789 spoile > 0123456789 spoil > 0123456789 spoi > 0123456789 spo > 0123456789 sp > 0123456789 s > 0123456789 > 0123456789 > 012345678 > 01234567 > 0123456 > 012345 > 01234 > 0123 > 012 > 01 > > > Reject (but score) the first two dishes, and then accept the > first dish that scores better than any you have yet seen (or the > last if you must and are very hungry). > > This algorithm will pick the best of five dishes about seven > times in twenty visits. > > -- > Richard Heathfield > Email: rjh at cpax dot org dot uk > "Usenet is a strange place" - dmr 29 July 1999 > Sig line 4 vacant - apply within
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