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Re: Can someone help ?

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Robam Kriztjan wrote:
> This is something better now:

It is not so much better that https://validator.w3.org/nu/#textarea 
reports no errors.  Were I you (what an alarming idea) I would fix the 
errors (there are three) and the warning too.  (When I was a programmer 
I always fixed warnings unless there was a very, very, very good reason 
not to; and then I would put a comment in the code justifying (let's 
hope) my decision not to fix them.)

I recognize that syntactically correct code can still fail to do what 
you want of it.  If you want help you will need to say precisely what 
specification your code is required to fulfil.  But note that no one is 
obliged to help you, and (this is important) if you behave like an utter 
twat even people who are naturally predisposed to help may be unwilling 
to do so.

> <html>
> <body>
> <canvas id="canvas" width="346" height="378"></canvas>
> <p></p>
> 
> <div style="display:none;">
> <img id="img1"
> src="img.jpg"
> width="346" height="378">
> </div>
> 
> 
> <script>
> var canvas = document.getElementById('canvas');
> var ctx = canvas.getContext('2d');
> var img = document.getElementById('img1');
> 
> img.addEventListener('load', e => {
> ctx.drawImage(img, 0, 0);
> var imgData = ctx.getImageData(0, 0, canvas.width, canvas.height);
> 
> var array1=new Array(4*canvas.width*canvas.height);
> 
> for (var i = 0; i < array1.length; i++) {
> array1[i]=0;
> }
> 
> 
> var r1=Math.round(Math.random()*255);
> var r2=Math.round(Math.random()*255);
> var r3=Math.round(Math.random()*255);
> var r4=Math.round(Math.random()*255);
> 
> for (var i = 0; i < imgData.data.length; i += 4) {
> if(array1[i]==1) continue;
> var a1=imgData.data[i];
> var a2=imgData.data[i+1];
> var a3=imgData.data[i+2];
> var a4=imgData.data[i+3];
> 
> 
> var r01 = Math.random() < 0.5 ? -1 : 1;
> var r02 = Math.random() < 0.5 ? -1 : 1;
> var r03 = Math.random() < 0.5 ? -1 : 1;
> var r04 = Math.random() < 0.5 ? -1 : 1;
> 
> r1=(a1+r01*Math.round(Math.random()*15))%255;
> r2=(a2+r02*Math.round(Math.random()*15))%255;
> r3=(a3+r03*Math.round(Math.random()*15))%255;
> r4=(a4+r04*Math.round(Math.random()*15))%255;
> 
> 
> for (var j = i+4; j < imgData.data.length; j += 4) {
> if(array1[j]==1) continue;
> if(a1==imgData.data[j]&&a2==imgData.data[j+1]&&a3==imgData.data[j+2]&&a4==imgData.data[j+3]) {
> imgData.data[j]=r1;
> imgData.data[j+1]=r2;
> imgData.data[j+2]=r3;
> imgData.data[j+3]=r4;
> array1[j]=1;
> }
> }
> 
> imgData.data[i]=r1;
> imgData.data[i+1]=r2;
> imgData.data[i+2]=r3;
> imgData.data[i+3]=r4;
> }
> 
> ctx.putImageData(imgData, 0, 0);
> });
> 
> 
> </script>
> </body>
> </html>
> 
> 
> But not what I exactly mean.
>   
> 
> 
> 
> A I
> 
> E-mail: ya12983 mail co m
> Telephone number: (372) 6861327
> 


-- 
When, once, reference was made to a statesman almost universally
recognized as one of the villains of this century, in order to
induce him to a negative judgment, he replied: "My situation is
so different from his, that it is not for me to pass judgment".
Ernst Specker on Paul Bernays

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Thread

Can someone help ? Kristjan Robam <he12457@hotmail.com> - 2021-02-06 07:44 -0800
  Re: Can someone help ? Peter <peterxpercival@hotmail.com> - 2021-02-06 20:38 +0000
    Re: Can someone help ? Robam Kriztjan <he12457@hotmail.com> - 2021-02-08 00:53 -0800
      Re: Can someone help ? Robam Kriztjan <he12457@hotmail.com> - 2021-02-08 01:40 -0800
        Re: Can someone help ? Robam Kriztjan <he12457@hotmail.com> - 2021-02-08 01:54 -0800
          Re: Can someone help ? Peter <peterxpercival@hotmail.com> - 2021-02-08 22:43 +0000
            Re: Can someone help ? Richard Heathfield <rjh@cpax.org.uk> - 2021-02-09 08:14 +0000
              Re: Can someone help ? I A <he12457@hotmail.com> - 2021-02-09 14:07 -0800
                Re: Can someone help ? I A <he12457@hotmail.com> - 2021-02-09 14:44 -0800
                Re: Can someone help ? Peter <peterxpercival@hotmail.com> - 2021-02-10 16:59 +0000
                Re: Can someone help ? I A <he12457@hotmail.com> - 2021-02-10 09:11 -0800
                Re: Can someone help ? David Brown <david.brown@hesbynett.no> - 2021-02-11 12:59 +0100
              Re: Can someone help ? Peter <peterxpercival@hotmail.com> - 2021-02-10 20:05 +0000

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