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Groups > comp.programming > #7606
| From | Daniel Bastos <dbastos@toledo.com> |
|---|---|
| Newsgroups | comp.programming |
| Subject | on solving recurrences |
| Date | 2017-03-21 16:13 -0300 |
| Organization | Aioe.org NNTP Server |
| Message-ID | <86y3vyh292.fsf@toledo.com> (permalink) |
Can you suggest a book that concerns precisely on solving recurrences
given my background? You'll see my background as I try my best at this
one. (I know Concrete Mathematics by Knuth et al, but as much I liked
their presentation of the Josephus problem, I think that book is too
advanced for me.) Thank you!
(*) Problem
Solve
T(n) = 1 if n = 0
= 2 T(n - 1) + 1 if n > 0
Remark. The only way I know how to solve this is by guessing. Here's
how I do it.
Solution. First I look at say T(8).
T(8) = 2 T(7) + 1
= 2 (2 T(6) + 1) + 1
= 2 (2 (2 T(5) + 1) + 1) + 1
= 2 (2 (2 (2 T(4) + 1) + 1) + 1) + 1
So I see a pattern emerging. I ``went down 4 levels'' and I found this:
= 2 (2 (2^2 T(4) + (1*2 + 1)) + 1) + 1
= 2 (2^3 T(4) + (1*2*2 + 1*2) + 1) + 1
= 2^4 T(4) + 1*2*2*2 + 1*2*2 + 1*2 + 1
= 2^4 T(4) + 2^3 + 2^2 + 2^1 + 2^0
So I must now discover what is Sum(2^i for i=0..n-1). Programming
verification (see below) makes clear that we don't actually need to find
that because it gets easy to see --- numerically --- that we have a case
for 2^n - 1.
Somehow
2^n - 1 = 2^n + Sum(2^i for i=0..n-1).
Thank you.
(*) Programming verification
def xrange(beg, end):
# Python's range(x,y) goes up to y - 1. We usually want to be
# inclusive.
return range(beg, end + 1)
def T0(n):
if n == 0:
return 1
elif n == 1:
return 3
else:
return 2**n + sum([2**i for i in xrange(0, n - 1)])
def T0r(n):
if n == 0:
return 1
else:
return 2 * T0r(n - 1) + 1
>>> [(t0(i), t0r(i)) for i in range(8)]
[(1, 1), (3, 3), (7, 7), (15, 15), (31, 31), (63, 63), (127, 127), (255, 255)]
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on solving recurrences Daniel Bastos <dbastos@toledo.com> - 2017-03-21 16:13 -0300
Re: on solving recurrences Ed Prochak <edprochak@gmail.com> - 2017-03-22 06:35 -0700
Re: on solving recurrences Daniel Bastos <dbastos@toledo.com> - 2017-03-23 19:06 -0300
Re: on solving recurrences Daniel Bastos <dbastos@toledo.com> - 2017-03-23 19:16 -0300
Re: on solving recurrences David Brown <david.brown@hesbynett.no> - 2017-03-24 09:53 +0100
Re: on solving recurrences David Brown <david.brown@hesbynett.no> - 2017-03-22 14:58 +0100
Re: on solving recurrences Daniel Bastos <dbastos@toledo.com> - 2017-03-23 19:11 -0300
Re: on solving recurrences David Brown <david.brown@hesbynett.no> - 2017-03-24 09:48 +0100
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