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| Path | csiph.com!aioe.org!.POSTED!not-for-mail |
|---|---|
| From | Kaz Kylheku <336-986-7787@kylheku.com> |
| Newsgroups | comp.programming |
| Subject | Re: on expressing o() in terms of O(), Omega() or Theta() |
| Date | Mon, 20 Mar 2017 19:33:51 +0000 (UTC) |
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| Lines | 50 |
| Message-ID | <20170320120639.205@kylheku.com> (permalink) |
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On 2017-03-20, Daniel Bastos <dbastos@toledo.com> wrote: > Kaz Kylheku <336-986-7787@kylheku.com> writes: > >> On 2017-03-19, Daniel Bastos <dbastos@toledo.com> wrote: >>> Is it possible to *define* o() in terms of O(), Omega() or Theta() --- or >>> any combination of them? >> >> To warm up, first define <= and >= in terms of =. > > I don't think that's very easy to do. That depends. We can define 'x = a' in terms of 'x <= a' and 'x >= a' very easily like this: x = a <==iff===> x <= a and x >= a This reasoning over to the big Oh family which are defined using inequalities. Suppose we use the Knuth definition of Omega, which is the inverse of big Oh: f is O(g) <==> g is Omega(f) If both are true, then, I think: f is Theta(g): f = Theta(g) iff f = O(g) and g = Omega(f) If f grows no faster than g, but also at least as fast as g, then it grows exactly as fast as g! What's left is to show that using the expanded definition of what these notations mean: the quantified expressions over inequalities. The definition of Theta involves the binding of two constants under existential quantifiers, and asserting that one function is sandwiched between these two constant factors of the other, for sufficiently large values of the independent variable. Now about o in terms of Theta and the others: which little o definition are you using? The problem is that the definitions of big and little O are very similar. There is a hair-splitting difference which shows up as in one logical quantifier being universal in little Oh whereas it is existential in big Oh. f = o(g) asserts that there is a sufficiently large value of the independent variable x such that for all positive constants C, |f(x)| <= C|g(x)|. Whereas big O only asserts that this is true for some sufficiently large, positive constant C, not for all positive constants C. Basically, you have to work with the expanded versions of these definitions and see if or how you can work one in terms of the others. Is there some logical combination of several of them which will derive the one you want (using whatever manipulation is necessary: reshuffling the quantifiers, etc).
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on expressing o() in terms of O(), Omega() or Theta() Daniel Bastos <dbastos@toledo.com> - 2017-03-19 20:12 -0300
Re: on expressing o() in terms of O(), Omega() or Theta() Kaz Kylheku <336-986-7787@kylheku.com> - 2017-03-20 03:13 +0000
Re: on expressing o() in terms of O(), Omega() or Theta() Daniel Bastos <dbastos@toledo.com> - 2017-03-20 15:44 -0300
Re: on expressing o() in terms of O(), Omega() or Theta() Kaz Kylheku <336-986-7787@kylheku.com> - 2017-03-20 19:33 +0000
Re: on expressing o() in terms of O(), Omega() or Theta() Daniel Bastos <dbastos@toledo.com> - 2017-03-21 08:17 -0300
Re: on expressing o() in terms of O(), Omega() or Theta() Daniel Bastos <dbastos@toledo.com> - 2017-03-28 21:10 -0300
Re: on expressing o() in terms of O(), Omega() or Theta() Daniel Bastos <dbastos@toledo.com> - 2017-03-29 09:22 -0300
Re: on expressing o() in terms of O(), Omega() or Theta() Daniel Bastos <dbastos@toledo.com> - 2017-05-04 08:57 -0300
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