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Groups > comp.programming.threads > #922
| From | "aminer" <aminer@videotron.ca> |
|---|---|
| Newsgroups | comp.programming.threads, comp.programming |
| Subject | Re: About the availability and efficiency... |
| Date | 2012-06-03 20:56 -0500 |
| Organization | A noiseless patient Spider |
| Message-ID | <jqh13v$1ve$1@dont-email.me> (permalink) |
| References | <jqh0bs$tv6$1@dont-email.me> |
Cross-posted to 2 groups.
Hello again, I have also corrected a typo in my other page about a jackson network problem... Here it is: http://pages.videotron.com/aminer/ParallelGaussSeidel/jackson1.htm Thank you. Amine Moulay Ramdane "aminer" <aminer@videotron.ca> wrote in message news:jqh0bs$tv6$1@dont-email.me... > Hello, > > I have corrected an error in my page about the availability and > efficiency, the utilization is equal to the arrival rate divided by > the servive rate, not the inverse.. > > And here is the part that i have corrected: > > As you have noticed, i have finally arrived to the following > mathematical model of our Jackson network that model an Enterprise > website: > > > T = Ni /A = (Nn + Ns + Nc) /A > = (((A/Ss)/n) / (1 -((A/Ss)/n)) + (A/Sn) / (1 -(A/Sn)) > + (A/Sc) / (1 -(A/Sc))) / A > > > > T: is the average response time.. > > > > So read it carefully an you will notice that this mathematical > model also can simulate and predict an intranet website behavior > or an internet website.. > > > > First look at the first factor ((A/Ss)/n) / (1 -((A/Ss)/n)) > is equal to (A/((Ss x n) - A) in our mathematical model, > as you have noticed as n (number of servers) grows > this will make the denominator grow and this will make > (A/((Ss x n) - A) smaller, that's good for the response time... > > > Now let's look at the other factors in this mathematical > model: > > > > IF the system is an Intranet, and for example the local > area network Sn is faster than the multiserver, that means: > > > We have Sn >> Ss, and that means => Sn /A >> Ss /A => that the > Knee in the server side can be reached more quickly than the > Knee in the network node of our Jackson network, so that > the bottleneck becomes the server node. > > > In the other hand if: > > > > Ss >> Sn => Ss /A >> Sn / A => the Knee in the M/M/1 network > node can be reached more quickly, so that the network node in > the Jackson network becomes the bottleneck. > > > > Please read more on my page: > > http://pages.videotron.com/aminer/efficiency_availability.htm > > > > Thank you. > Amine Moulay Ramdane. > > > > >
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About the availability and efficiency... "aminer" <aminer@videotron.ca> - 2012-06-03 20:43 -0500 Re: About the availability and efficiency... "aminer" <aminer@videotron.ca> - 2012-06-03 20:56 -0500
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