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Booting process 0: how to find out its full path?

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Hello,

I am working on a shell that would replace COMMAND.COM and I wonder: is
there any way I can figure out where my shell is, once it is executed
by the MS-DOS kernel?

By default MS-DOS launches whatever it finds at [BOOTDRV]:\COMMAND.COM.
This situation is easy, but there is also the possibility that the shell
was configured through a "SHELL" or "SHELLHIGH" CONFIG.SYS directive:
SHELL=X:\EXOTIC\PATH\CUSTOM.COM

I am unable to find a way to discover the above path. Any ideas if this
is feasible at all? I went through RBIL but with no luck so far.

The environment contains the full path/name of the executed program,
but this does not apply to process 0, as the MS-DOS kernel does not
allocate any environment for it (env segment in PSP = 0x0000).

Mateusz

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Thread

Booting process 0: how to find out its full path? Mateusz Viste <mateusz@xyz.invalid> - 2021-11-16 10:44 +0100
  Re: Booting process 0: how to find out its full path? "Auric__" <not.my.real@email.address> - 2021-11-16 16:54 +0000
    Re: Booting process 0: how to find out its full path? Mateusz Viste <mateusz@xyz.invalid> - 2021-11-16 18:07 +0100
      Re: Booting process 0: how to find out its full path? "Auric__" <not.my.real@email.address> - 2021-11-16 18:49 +0000
        Re: Booting process 0: how to find out its full path? Mateusz Viste <mateusz@xyz.invalid> - 2021-11-16 20:46 +0100
  Re: Booting process 0: how to find out its full path? JJ <jj4public@gmail.com> - 2021-11-17 08:23 +0700
    Re: Booting process 0: how to find out its full path? Mateusz Viste <mateusz@xyz.invalid> - 2021-11-17 09:11 +0100

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