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| Started by | Tim <jtim.arnold@gmail.com> |
|---|---|
| First post | 2014-11-06 08:37 -0800 |
| Last post | 2014-11-07 14:50 -0500 |
| Articles | 5 — 4 participants |
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help with creating dict from string Tim <jtim.arnold@gmail.com> - 2014-11-06 08:37 -0800
Re: help with creating dict from string Peter Otten <__peter__@web.de> - 2014-11-06 18:40 +0100
Re: help with creating dict from string Tim <jtim.arnold@gmail.com> - 2014-11-06 11:18 -0800
Re: help with creating dict from string <versalytics@gmail.com> - 2014-11-06 22:09 +0000
Re: help with creating dict from string Dennis Lee Bieber <wlfraed@ix.netcom.com> - 2014-11-07 14:50 -0500
| From | Tim <jtim.arnold@gmail.com> |
|---|---|
| Date | 2014-11-06 08:37 -0800 |
| Subject | help with creating dict from string |
| Message-ID | <cc511471-6929-4f15-8b07-5db374103e1a@googlegroups.com> |
hi, I have strings coming in with this format:
'[one=two, three=four five, six, seven=eight]'
and I want to create from that string, this dictionary:
{'one':'two', 'three':'four five', 'six':True, 'seven':'eight'}
These are option strings, with each key-value pair separated by commas.
Where there is a value, the key-value pair is separated by '='.
This is how I started (where s is the string):
s = s.replace('[','').replace(']','')
s = [x.split('=') for x in s.split(',')]
[['one', 'two'], [' three', 'four five'], [' six'], [' seven', 'eight']]
I know I can iterate and strip each item, fixing single-element keys as I go.
I just wondered if I'm missing something more elegant. If it wasn't for the leading spaces and the boolean key, the dict() constructor would have been sweet.
thanks for any ideas,
--Tim
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| From | Peter Otten <__peter__@web.de> |
|---|---|
| Date | 2014-11-06 18:40 +0100 |
| Message-ID | <mailman.15549.1415295657.18130.python-list@python.org> |
| In reply to | #80338 |
Tim wrote:
> hi, I have strings coming in with this format:
>
> '[one=two, three=four five, six, seven=eight]'
>
> and I want to create from that string, this dictionary:
> {'one':'two', 'three':'four five', 'six':True, 'seven':'eight'}
>
> These are option strings, with each key-value pair separated by commas.
> Where there is a value, the key-value pair is separated by '='.
>
> This is how I started (where s is the string):
> s = s.replace('[','').replace(']','')
> s = [x.split('=') for x in s.split(',')]
>
> [['one', 'two'], [' three', 'four five'], [' six'], [' seven',
> [['eight']]
>
> I know I can iterate and strip each item, fixing single-element keys as I
> go.
>
> I just wondered if I'm missing something more elegant. If it wasn't for
> the leading spaces and the boolean key, the dict() constructor would have
> been sweet.
Not everything has to be a one-liner ;) If it works I don't think something
>>> s = '[one=two, three=four five, six, seven=eight]'
>>> def fix(pair):
... key, eq, value = pair.partition("=")
... return key.strip(), value if eq else True
...
>>> dict(fix(t) for t in s.strip("[]").split(","))
{'three': 'four five', 'seven': 'eight', 'one': 'two', 'six': True}
is particularly inelegant. Are you sure that your grammar is not more
complex than your example, e. g. that "," cannot occur in the values?
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| From | Tim <jtim.arnold@gmail.com> |
|---|---|
| Date | 2014-11-06 11:18 -0800 |
| Message-ID | <eb42036a-e89a-45c8-83c0-72fab2c20a16@googlegroups.com> |
| In reply to | #80340 |
On Thursday, November 6, 2014 12:41:10 PM UTC-5, Peter Otten wrote:
> Tim wrote:
>
> > hi, I have strings coming in with this format:
> >
> > '[one=two, three=four five, six, seven=eight]'
> >
> > and I want to create from that string, this dictionary:
> > {'one':'two', 'three':'four five', 'six':True, 'seven':'eight'}
> >
> > snip
>
> Not everything has to be a one-liner ;) If it works I don't think something
>
> >>> s = '[one=two, three=four five, six, seven=eight]'
> >>> def fix(pair):
> ... key, eq, value = pair.partition("=")
> ... return key.strip(), value if eq else True
> ...
> >>> dict(fix(t) for t in s.strip("[]").split(","))
> {'three': 'four five', 'seven': 'eight', 'one': 'two', 'six': True}
>
> is particularly inelegant. Are you sure that your grammar is not more
> complex than your example, e. g. that "," cannot occur in the values?
hi Peter,
I definitely wouldn't say that is inelegant :-)
I had never used the partition method and I didn't realize (or maybe remember) that strip could take a string of characters, not just one.
Oh yes, I am positive about the grammar--no commas are allowed in the values. I think your solution is pretty elegant. Thanks for your help!
--Tim
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| From | <versalytics@gmail.com> |
|---|---|
| Date | 2014-11-06 22:09 +0000 |
| Message-ID | <mailman.15550.1415312060.18130.python-list@python.org> |
| In reply to | #80341 |
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On Thursday, November 6, 2014 12:41:10 PM UTC-5, Peter Otten wrote:
> Tim wrote:
>
> > hi, I have strings coming in with this format:
> >
> > '[one=two, three=four five, six, seven=eight]'
> >
> > and I want to create from that string, this dictionary:
> > {'one':'two', 'three':'four five', 'six':True, 'seven':'eight'}
> >
> > snip
>
> Not everything has to be a one-liner ;) If it works I don't think something
>
> >>> s = '[one=two, three=four five, six, seven=eight]'
> >>> def fix(pair):
> ... key, eq, value = pair.partition("=")
> ... return key.strip(), value if eq else True
> ...
> >>> dict(fix(t) for t in s.strip("[]").split(","))
> {'three': 'four five', 'seven': 'eight', 'one': 'two', 'six': True}
>
> is particularly inelegant. Are you sure that your grammar is not more
> complex than your example, e. g. that "," cannot occur in the values?
hi Peter,
I definitely wouldn't say that is inelegant :-)
I had never used the partition method and I didn't realize (or maybe remember) that strip could take a string of characters, not just one.
Oh yes, I am positive about the grammar--no commas are allowed in the values. I think your solution is pretty elegant. Thanks for your help!
--Tim
--
This is a very clever solution. I just came across the need for something similar. Good question, excellent solution. Thank you!
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| From | Dennis Lee Bieber <wlfraed@ix.netcom.com> |
|---|---|
| Date | 2014-11-07 14:50 -0500 |
| Message-ID | <mailman.15574.1415389849.18130.python-list@python.org> |
| In reply to | #80338 |
On Thu, 6 Nov 2014 08:37:00 -0800 (PST), Tim <jtim.arnold@gmail.com>
declaimed the following:
>hi, I have strings coming in with this format:
>
> '[one=two, three=four five, six, seven=eight]'
>
>and I want to create from that string, this dictionary:
> {'one':'two', 'three':'four five', 'six':True, 'seven':'eight'}
>
>These are option strings, with each key-value pair separated by commas.
>Where there is a value, the key-value pair is separated by '='.
>
>This is how I started (where s is the string):
> s = s.replace('[','').replace(']','')
> s = [x.split('=') for x in s.split(',')]
>
> [['one', 'two'], [' three', 'four five'], [' six'], [' seven', 'eight']]
You state you want a dictionary -- so why are you mucking about with
generating a list of lists?
>>> inp = "[one=two, three=four five, six, seven=eight]"
>>>
>>> inp = inp.strip("[]")
>>> inp
'one=two, three=four five, six, seven=eight'
>>> entries = inp.split(",")
>>> entries
['one=two', ' three=four five', ' six', ' seven=eight']
>>> for entry in entries:
... kv = entry.split("=")
... if len(kv) < 2:
... dct[kv[0].strip()] = True
... else:
... dct[kv[0].strip()] = kv[1].strip()
...
>>> print dct
{'seven': 'eight', 'six': True, 'three': 'four five', 'one': 'two'}
Note: this is a dictionary -- by definition the order of the k-v pairs
is not predefined, and may change with each pair that is added (though it
is peculiar that for this data set the display returns in reverse order).
>
>I know I can iterate and strip each item, fixing single-element keys as I go.
It's simple, it is easy to understand, and way more elegant than trying
to create some PERLism.
--
Wulfraed Dennis Lee Bieber AF6VN
wlfraed@ix.netcom.com HTTP://wlfraed.home.netcom.com/
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