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| Started by | Chris Angelico <rosuav@gmail.com> |
|---|---|
| First post | 2014-11-03 22:09 +1100 |
| Last post | 2014-11-03 22:09 +1100 |
| Articles | 1 — 1 participant |
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Re: Dictionaries with variable default. Chris Angelico <rosuav@gmail.com> - 2014-11-03 22:09 +1100
| From | Chris Angelico <rosuav@gmail.com> |
|---|---|
| Date | 2014-11-03 22:09 +1100 |
| Subject | Re: Dictionaries with variable default. |
| Message-ID | <mailman.15425.1415013405.18130.python-list@python.org> |
On Mon, Nov 3, 2014 at 10:04 PM, Antoon Pardon
<antoon.pardon@rece.vub.ac.be> wrote:
> Is it possible to have a default dictionary where the default is dependant
> on the key?
>
> I was hoping something like this might work:
>>>> m = defaultdict(lambda key: key+1)
>
> But it obviously doesn't:
>>>> m[3]
>
> Traceback (most recent call last):
> File "<stdin>", line 1, in <module>
> TypeError: <lambda>() takes exactly 1 argument (0 given)
Yes, but not with the defaultdict. Instead, just implement __missing__:
class KeyPlusOne(dict):
def __missing__(self, key): return key+1
ChrisA
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