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Groups > comp.lang.python > #78532 > unrolled thread
| Started by | cl@isbd.net |
|---|---|
| First post | 2014-10-01 10:58 +0100 |
| Last post | 2014-10-01 13:19 +0100 |
| Articles | 3 on this page of 23 — 13 participants |
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How to show a dictionary sorted on a value within its data? cl@isbd.net - 2014-10-01 10:58 +0100
Re: How to show a dictionary sorted on a value within its data? Peter Otten <__peter__@web.de> - 2014-10-01 12:24 +0200
Re: How to show a dictionary sorted on a value within its data? cl@isbd.net - 2014-10-01 11:45 +0100
Re: How to show a dictionary sorted on a value within its data? Joel Goldstick <joel.goldstick@gmail.com> - 2014-10-01 06:56 -0400
Re: How to show a dictionary sorted on a value within its data? cl@isbd.net - 2014-10-01 13:16 +0100
Re: How to show a dictionary sorted on a value within its data? Peter Otten <__peter__@web.de> - 2014-10-01 13:12 +0200
Re: How to show a dictionary sorted on a value within its data? Travis Griggs <travisgriggs@gmail.com> - 2014-10-01 21:57 -0700
Re: How to show a dictionary sorted on a value within its data? cl@isbd.net - 2014-10-02 10:40 +0100
Re: How to show a dictionary sorted on a value within its data? Marko Rauhamaa <marko@pacujo.net> - 2014-10-02 14:17 +0300
Re: How to show a dictionary sorted on a value within its data? Rustom Mody <rustompmody@gmail.com> - 2014-10-02 10:46 -0700
Re: How to show a dictionary sorted on a value within its data? Grant Edwards <invalid@invalid.invalid> - 2014-10-02 14:05 +0000
Re: How to show a dictionary sorted on a value within its data? cl@isbd.net - 2014-10-02 17:33 +0100
Re: How to show a dictionary sorted on a value within its data? Ian Kelly <ian.g.kelly@gmail.com> - 2014-10-02 13:15 -0600
Re: How to show a dictionary sorted on a value within its data? Grant Edwards <invalid@invalid.invalid> - 2014-10-02 19:36 +0000
Re: How to show a dictionary sorted on a value within its data? Dan Stromberg <drsalists@gmail.com> - 2014-10-02 13:06 -0700
Re: How to show a dictionary sorted on a value within its data? Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2014-10-03 09:16 +1000
Re: How to show a dictionary sorted on a value within its data? Chris Angelico <rosuav@gmail.com> - 2014-10-03 12:44 +1000
Re: How to show a dictionary sorted on a value within its data? Steven D'Aprano <steve@pearwood.info> - 2014-10-03 07:55 +0000
Re: How to show a dictionary sorted on a value within its data? Chris Angelico <rosuav@gmail.com> - 2014-10-03 18:09 +1000
Re: How to show a dictionary sorted on a value within its data? Chris Angelico <rosuav@gmail.com> - 2014-10-03 07:01 +1000
Re: How to show a dictionary sorted on a value within its data? Mark Lawrence <breamoreboy@yahoo.co.uk> - 2014-10-01 11:27 +0100
Re: How to show a dictionary sorted on a value within its data? Joel Goldstick <joel.goldstick@gmail.com> - 2014-10-01 06:37 -0400
Re: How to show a dictionary sorted on a value within its data? cl@isbd.net - 2014-10-01 13:19 +0100
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| From | Mark Lawrence <breamoreboy@yahoo.co.uk> |
|---|---|
| Date | 2014-10-01 11:27 +0100 |
| Message-ID | <mailman.14513.1412159254.18130.python-list@python.org> |
| In reply to | #78532 |
On 01/10/2014 10:58, cl@isbd.net wrote:
> I have a dictionary as follows:-
>
> {
> u'StarterAmps1': Row(id=4, ain=u'AIN3', name=u'StarterAmps1', conv=6834.374834509803, Description=u'Starter Amps'),
> u'LeisureVolts': Row(id=1, ain=u'AIN0', name=u'LeisureVolts', conv=29.01374215995874, Description=u'Leisure Volts'),
> u'RudderPos': Row(id=6, ain=u'AIN5', name=u'RudderPos', conv=0.028125, Description=u'Rudder Position'),
> u'xx': Row(id=7, ain=u'AIN6', name=u'xx', conv=0.028125, Description=u''),
> u'LeisureAmps1': Row(id=3, ain=u'AIN2', name=u'LeisureAmps1', conv=32.727273081945, Description=u'Leisure Amps'),
> u'StarterVolts': Row(id=2, ain=u'AIN1', name=u'StarterVolts', conv=28.94469628911757, Description=u'Starter Volts')
> }
>
> I want to output a menu to a user comprising some parts of the
> dictionary (ain and Description) sorted by ain.
>
> Is there some incantation of sorted() that will do what I want? I
> can't quite fathom out the 'key=' parameter needed to sort it by the
> tuple item. Maybe I need a cmp= ?
>
> E.g. I want to do something like:-
>
> for meas in sorted(adc.cfg, key=???):
> print(adc.cfg[meas].ain, adc.cfg[meas].Description)
>
> What's needed in the ???
>
IIRC one method involves using itemgetter from
https://docs.python.org/3/library/operator.html#module-operator
--
My fellow Pythonistas, ask not what our language can do for you, ask
what you can do for our language.
Mark Lawrence
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| From | Joel Goldstick <joel.goldstick@gmail.com> |
|---|---|
| Date | 2014-10-01 06:37 -0400 |
| Message-ID | <mailman.14514.1412159881.18130.python-list@python.org> |
| In reply to | #78532 |
On Wed, Oct 1, 2014 at 5:58 AM, <cl@isbd.net> wrote:
> I have a dictionary as follows:-
>
> {
> u'StarterAmps1': Row(id=4, ain=u'AIN3', name=u'StarterAmps1', conv=6834.374834509803, Description=u'Starter Amps'),
> u'LeisureVolts': Row(id=1, ain=u'AIN0', name=u'LeisureVolts', conv=29.01374215995874, Description=u'Leisure Volts'),
> u'RudderPos': Row(id=6, ain=u'AIN5', name=u'RudderPos', conv=0.028125, Description=u'Rudder Position'),
> u'xx': Row(id=7, ain=u'AIN6', name=u'xx', conv=0.028125, Description=u''),
> u'LeisureAmps1': Row(id=3, ain=u'AIN2', name=u'LeisureAmps1', conv=32.727273081945, Description=u'Leisure Amps'),
> u'StarterVolts': Row(id=2, ain=u'AIN1', name=u'StarterVolts', conv=28.94469628911757, Description=u'Starter Volts')
> }
Is Row a function? Or do you have a key with a tuple as the value?
>
> I want to output a menu to a user comprising some parts of the
> dictionary (ain and Description) sorted by ain.
>
> Is there some incantation of sorted() that will do what I want? I
> can't quite fathom out the 'key=' parameter needed to sort it by the
> tuple item. Maybe I need a cmp= ?
>
> E.g. I want to do something like:-
>
> for meas in sorted(adc.cfg, key=???):
> print(adc.cfg[meas].ain, adc.cfg[meas].Description)
>
> What's needed in the ???
>
> --
> Chris Green
> ·
You might read here:
http://www.pythoncentral.io/how-to-sort-python-dictionaries-by-key-or-value/
> --
> https://mail.python.org/mailman/listinfo/python-list
--
Joel Goldstick
http://joelgoldstick.com
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| From | cl@isbd.net |
|---|---|
| Date | 2014-10-01 13:19 +0100 |
| Message-ID | <748tfb-5lu.ln1@chris.zbmc.eu> |
| In reply to | #78536 |
Joel Goldstick <joel.goldstick@gmail.com> wrote:
> On Wed, Oct 1, 2014 at 5:58 AM, <cl@isbd.net> wrote:
> > I have a dictionary as follows:-
> >
> > {
> > u'StarterAmps1': Row(id=4, ain=u'AIN3', name=u'StarterAmps1', conv=6834.374834509803,
> Description=u'Starter Amps'),
> > u'LeisureVolts': Row(id=1, ain=u'AIN0', name=u'LeisureVolts', conv=29.01374215995874,
> Description=u'Leisure Volts'),
> > u'RudderPos': Row(id=6, ain=u'AIN5', name=u'RudderPos', conv=0.028125,
> Description=u'Rudder Position'),
> > u'xx': Row(id=7, ain=u'AIN6', name=u'xx', conv=0.028125, Description=u''),
> > u'LeisureAmps1': Row(id=3, ain=u'AIN2', name=u'LeisureAmps1', conv=32.727273081945,
> Description=u'Leisure Amps'),
> > u'StarterVolts': Row(id=2, ain=u'AIN1', name=u'StarterVolts', conv=28.94469628911757,
> Description=u'Starter Volts')
> > }
>
> Is Row a function? Or do you have a key with a tuple as the value?
Row is a namedtuple, the dictionary is extracted from a database with
a row factory so the namedtuple names are the column names. It means
that if I change a column name then most things continue to work
without any code changes, and also I can refer to items in the tuple
by name of course.
I have the answer to my question in other responses.
--
Chris Green
·
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