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Groups > comp.lang.python > #198067
| Subject | Re: ''.join([bin(i)[2:].zfill(8) for i in flag]) |
|---|---|
| Newsgroups | comp.lang.python |
| References | <nnd$45c195ac$47172e6f@35c50d4e9a8c02a9> <bin-20260924000855@ram.dialup.fu-berlin.de> |
| From | Johann 'Myrkraverk' Oskarsson <johann@myrkraverk.invalid> |
| Organization | Watcom Pro Ltd. |
| Message-ID | <qnwtS.229030$RI1.198964@fx04.ams4> (permalink) |
| Date | 2026-09-25 23:25 +0800 |
On 9/24/2026 7:09 AM, Stefan Ram wrote:
> Johann 'Myrkraverk' Oskarsson <johann@myrkraverk.invalid> wrote or quoted:
>> As the topic says, is
>> ''.join([bin(i)[2:].zfill(8) for i in flag])
>> really the most Pythonic way to do this?
> . . .
>> I mean, isn't there a regular print-to-string-format function, something
>> akin to C's sprintf(), that does this in a more succinct way?
>
> Like,
>
> ''.join( f'{i:08b}' for i in flag )
>
> ?
>
>> Here, `flag` is a string variable, if it's not clear from the con-
>> text.
>
> If "flag" would be a string, then "i" would be a string too,
> but "bin" expects an integer.
Mea culpa, as Julius Caesar would say it. I missed the fact that the
string in question has a b in front of it, like this.
b'this is some string.'
And that indeed turns the string into a sequence of bytes. So much to
learn, so little Python.
Best wishes, and happy Python.
--
Johann | email: invalid -> com | http://www.myrkraverk.com/blog/
I'm not from the Internet, I just work there. | via Easynews.com
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''.join([bin(i)[2:].zfill(8) for i in flag]) Johann 'Myrkraverk' Oskarsson <johann@myrkraverk.invalid> - 2026-09-24 06:42 +0800
Re: ''.join([bin(i)[2:].zfill(8) for i in flag]) ram@zedat.fu-berlin.de (Stefan Ram) - 2026-09-23 23:09 +0000
Re: format_binary Lawrence D’Oliveiro <ldo@nz.invalid> - 2026-09-24 02:01 +0000
Re: format_binary Jon Ribbens <jon+usenet@unequivocal.eu> - 2026-09-24 06:57 +0000
Re: ''.join([bin(i)[2:].zfill(8) for i in flag]) Johann 'Myrkraverk' Oskarsson <johann@myrkraverk.invalid> - 2026-09-25 23:25 +0800
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