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Groups > comp.lang.python > #82293
| References | <5488634e$0$2130$426a74cc@news.free.fr> <1967177562.5434671.1418227803051.JavaMail.root@sequans.com> |
|---|---|
| Date | 2014-12-11 03:16 +1100 |
| Subject | Re: How to detect that a function argument is the default one |
| From | Chris Angelico <rosuav@gmail.com> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.16814.1418228205.18130.python-list@python.org> (permalink) |
On Thu, Dec 11, 2014 at 3:10 AM, Jean-Michel Pichavant <jeanmichel@sequans.com> wrote: > ----- Original Message ----- >> From: "ast" <nomail@invalid.com> >> I have the idea to write: >> >> def __init__(center=(0,0), radius=10, mass=None)): >> >> if mass == None: >> self.mass = radius**2 >> else: >> self.mass = mass >> >> but maybe Python provides something clever. >> >> Thx > > If you like one-liners, > > def __init__(self, center=(0,0), radius=10, mass=None): > self.center = center > self.radius = radius > self.mass = (mass is None and radius**2) or mass Leaving aside the obvious point that not everything needs to be a one-liner, there is a MUCH better way to spell this: the if/else ternary expression. self.mass = radius**2 if mass is None else mass > But there's an issue with that solution: self.mass being computed during the instance initialization, what if radius is changing ? > > c1 = Circle((0,0), 10, None) > print c1.mass > 20 > c1.radius = 20 > print c1.mass > 20 # that is unexpected > > Everytime an attribute is computed from another attribute, it should ring a python bell : property > > def __init__(self, center, radius, mass): > self.center = center > self.radius = radius > self._mass = mass > > @property > def mass(self): > return self._mass if self._mass is not None else self.radius*2 > > > c1 = Circle((0,0), 10, None) > print c1.mass > 20 > c1.radius = 20 > print c1.mass > 40 I think that juuuuuust miiiiight count as scope creep :) Though it does highlight an interesting point, namely that sometimes the state of "argument wasn't specified" needs to carry through into an object's "attribute wasn't specified". > Note : what is the mass of a circle ? Fortunately for us, this is a programming class, not a philosophical one. Maybe the circles in question are being cast in steel? :) ChrisA
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How to detect that a function argument is the default one "ast" <nomail@invalid.com> - 2014-12-10 16:14 +0100
Re: How to detect that a function argument is the default one Skip Montanaro <skip.montanaro@gmail.com> - 2014-12-10 09:29 -0600
Re: How to detect that a function argument is the default one "ast" <nomail@invalid.com> - 2014-12-10 16:45 +0100
Re: How to detect that a function argument is the default one Marko Rauhamaa <marko@pacujo.net> - 2014-12-10 18:33 +0200
Re: How to detect that a function argument is the default one Chris Angelico <rosuav@gmail.com> - 2014-12-11 03:16 +1100
Re: How to detect that a function argument is the default one wxjmfauth@gmail.com - 2014-12-10 12:08 -0800
Re: How to detect that a function argument is the default one "ast" <nomail@invalid.com> - 2014-12-10 22:17 +0100
Re: How to detect that a function argument is the default one Ian Kelly <ian.g.kelly@gmail.com> - 2014-12-11 11:03 -0700
Re: How to detect that a function argument is the default one Ian Kelly <ian.g.kelly@gmail.com> - 2014-12-11 11:07 -0700
Re: How to detect that a function argument is the default one Ned Batchelder <ned@nedbatchelder.com> - 2014-12-10 11:19 -0500
Re: How to detect that a function argument is the default one Ian Kelly <ian.g.kelly@gmail.com> - 2014-12-10 09:20 -0700
Re: How to detect that a function argument is the default one Tony the Tiger <tony@tiger.invalid> - 2014-12-11 19:45 +0000
Re: How to detect that a function argument is the default one Ben Finney <ben+python@benfinney.id.au> - 2014-12-12 10:03 +1100
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