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| References | (1 earlier) <m4kn66$ma3$1@ger.gmane.org> <1416491999.209592.193345213.3A6FF9A4@webmail.messagingengine.com> <CAPTjJmr5NWMFCfU8jaNd2g2f9cQ1y+zO3qT7yVcC_m9vKXN6fw@mail.gmail.com> <1416505379.268157.193439717.66E319D4@webmail.messagingengine.com> <CALwzid=qc66rGfr2nVM19bK3GfNQ4PUj2=3nzp0bEGzfW--1CA@mail.gmail.com> |
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| From | Ian Kelly <ian.g.kelly@gmail.com> |
| Date | 2014-11-20 11:09 -0700 |
| Subject | Re: python 2.7 and unicode (one more time) |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.16039.1416507018.18130.python-list@python.org> (permalink) |
On Thu, Nov 20, 2014 at 11:06 AM, Ian Kelly <ian.g.kelly@gmail.com> wrote: > On Thu, Nov 20, 2014 at 10:42 AM, <random832@fastmail.us> wrote: >> and it means you can't safely >> blindly use %s with an unknown object. > > You can't safely do this anyway. Whether it's %s with a str and a > unicode, or %s with a unicode and a str, *something* is going to have > to be implicitly encoded or decoded, and if ascii doesn't happen to be > the correct encoding then the result will be either an error or a > silent failure. Also note that if you use %r instead of %s, you'll get the result you want (although the unicode string will be quoted rather than encoded).
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Re: python 2.7 and unicode (one more time) Ian Kelly <ian.g.kelly@gmail.com> - 2014-11-20 11:09 -0700
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