Groups | Search | Server Info | Keyboard shortcuts | Login | Register [http] [https] [nntp] [nntps]
Groups > comp.lang.python > #78687
| Path | csiph.com!v102.xanadu-bbs.net!xanadu-bbs.net!goblin3!goblin1!goblin.stu.neva.ru!news.astraweb.com!border5.a.newsrouter.astraweb.com!bcyclone02.am1.xlned.com!bcyclone02.am1.xlned.com!newsfeed.xs4all.nl!newsfeed3.news.xs4all.nl!xs4all!post.news.xs4all.nl!not-for-mail |
|---|---|
| Return-Path | <python-python-list@m.gmane.org> |
| X-Original-To | python-list@python.org |
| Delivered-To | python-list@mail.python.org |
| X-Spam-Status | OK 0.000 |
| X-Spam-Evidence | '*H*': 1.00; '*S*': 0.00; '#print': 0.09; 'filename': 0.09; 'fname': 0.09; 'function:': 0.09; 'occurrences': 0.09; 'received:80.91': 0.09; 'received:80.91.229': 0.09; 'received:gmane.org': 0.09; 'received:list': 0.09; 'val': 0.09; 'def': 0.12; 'count,': 0.16; 'dict': 0.16; 'increment': 0.16; 'pairs': 0.16; 'received:80.91.229.3': 0.16; 'received:dip0.t-ipconnect.de': 0.16; 'received:plane.gmane.org': 0.16; 'received:t-ipconnect.de': 0.16; 'sorting': 0.16; 'subject:top': 0.16; 'skip:# 20': 0.16; 'wrote:': 0.18; 'all,': 0.19; 'bit': 0.19; "skip:' 30": 0.19; 'split': 0.19; 'subject:Issue': 0.19; 'written': 0.21; 'print': 0.22; 'header :User-Agent:1': 0.23; 'simpler': 0.24; 'sort': 0.25; 'first,': 0.26; 'header:X-Complaints-To:1': 0.27; 'point': 0.28; 'function': 0.29; 'skip:p 30': 0.29; 'words': 0.29; 'characters': 0.30; 'skip:( 20': 0.30; 'gives': 0.31; 'keys': 0.31; 'values.': 0.31; 'file': 0.32; 'figure': 0.32; "can't": 0.35; 'something': 0.35; 'convert': 0.35; 'late': 0.35; 'but': 0.35; 'possible': 0.36; 'effort': 0.37; 'too': 0.37; 'list': 0.37; 'to:addr:python-list': 0.38; 'fact': 0.38; 'to:addr:python.org': 0.39; 'skip:p 20': 0.39; 'received:org': 0.40; 'first': 0.61; 'such': 0.63; 'total': 0.65; 'here': 0.66; 'reverse': 0.68; 'apart': 0.72; 'subject:printing': 0.84 |
| X-Injected-Via-Gmane | http://gmane.org/ |
| To | python-list@python.org |
| From | Peter Otten <__peter__@web.de> |
| Subject | Re: Issue in printing top 20 dictionary items by dictionary value |
| Date | Sat, 04 Oct 2014 12:20:07 +0200 |
| Organization | None |
| References | <loom.20141004T110701-553@post.gmane.org> |
| Mime-Version | 1.0 |
| Content-Type | text/plain; charset="ISO-8859-1" |
| Content-Transfer-Encoding | 7Bit |
| X-Gmane-NNTP-Posting-Host | p57bda5c6.dip0.t-ipconnect.de |
| User-Agent | KNode/4.13.3 |
| X-BeenThere | python-list@python.org |
| X-Mailman-Version | 2.1.15 |
| Precedence | list |
| List-Id | General discussion list for the Python programming language <python-list.python.org> |
| List-Unsubscribe | <https://mail.python.org/mailman/options/python-list>, <mailto:python-list-request@python.org?subject=unsubscribe> |
| List-Archive | <http://mail.python.org/pipermail/python-list/> |
| List-Post | <mailto:python-list@python.org> |
| List-Help | <mailto:python-list-request@python.org?subject=help> |
| List-Subscribe | <https://mail.python.org/mailman/listinfo/python-list>, <mailto:python-list-request@python.org?subject=subscribe> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.14597.1412418025.18130.python-list@python.org> (permalink) |
| Lines | 70 |
| NNTP-Posting-Host | 2001:888:2000:d::a6 |
| X-Trace | 1412418025 news.xs4all.nl 2974 [2001:888:2000:d::a6]:55924 |
| X-Complaints-To | abuse@xs4all.nl |
| X-Received-Bytes | 5057 |
| X-Received-Body-CRC | 1284914455 |
| Xref | csiph.com comp.lang.python:78687 |
Show key headers only | View raw
Shiva wrote:
> Hi All,
>
> I have written a function that
> -reads a file
> -splits the words and stores it in a dictionary as word(key) and the total
> count of word in file (value).
>
> I want to print the words with top 20 occurrences in the file in reverse
> order - but can't figure it out. Here is my function:
>
> def print_top(filename):
>
> #Open a file
> path = '/home/BCA/Documents/LearnPython/ic/'
> fname = path + filename
> print ('filename: ',fname)
> filetext = open(fname)
>
> #Read the file
> textstorage={}
>
> #print(type(textstorage))
> readall = filetext.read().lower()
> eachword = set(readall.split())
>
> #store split words as keys in dictionary
> for w in eachword:
> textstorage[w] = readall.count(w)
Using count() here is very inefficient. A better approach is to increment
the dict value:
for w in readall.split():
textstorage[w] = textstorage.get(w, 0) + 1
>
> #print top 20 items in dictionary by decending order of val
> # This bit is what I can't figure out.
>
> for dkey in (textstorage.keys()):
> print(dkey,sorted(textstorage[dkey]))??
Apart from the fact that you are sorting characters in the word at that
point the sorting effort is already too late -- you need to sort the dict
keys by the corresponding dict values.
It is possible to write a get_value() function such that
sorted(textstorage, key=get_value, reverse=True)
gives the keys in the right order, but perhaps it is simpler to convert
textstorage into a list of (count, word) pairs first, something like
pairs = [(42, "blue"), (17, "red"), (77, "black"), ...]
When you sort that list
most_common_words = sorted(pairs, reverse=True)
you automatically get (count, word) pairs in the right order and can print
the first 20 with
for count, word in most_common_words[:20]:
print(word, count)
PS: Once you have it all working have a look at collections.Counter...
Back to comp.lang.python | Previous | Next | Find similar | Unroll thread
Re: Issue in printing top 20 dictionary items by dictionary value Peter Otten <__peter__@web.de> - 2014-10-04 12:20 +0200
csiph-web