Groups | Search | Server Info | Keyboard shortcuts | Login | Register [http] [https] [nntp] [nntps]
Groups > comp.lang.python > #81819
| Path | csiph.com!v102.xanadu-bbs.net!xanadu-bbs.net!feeder.erje.net!eu.feeder.erje.net!bloom-beacon.mit.edu!bloom-beacon.mit.edu!panix!gordon |
|---|---|
| From | John Gordon <gordon@panix.com> |
| Newsgroups | comp.lang.python |
| Subject | Re: Parsing XML Using XPATH for Python |
| Date | Tue, 2 Dec 2014 22:52:27 +0000 (UTC) |
| Organization | PANIX Public Access Internet and UNIX, NYC |
| Lines | 80 |
| Message-ID | <m5lfrb$88d$1@reader1.panix.com> (permalink) |
| References | <a1a70942-6740-4de5-b41e-57a71fb36910@googlegroups.com> |
| NNTP-Posting-Host | panix2.panix.com |
| X-Trace | reader1.panix.com 1417560747 8461 166.84.1.2 (2 Dec 2014 22:52:27 GMT) |
| X-Complaints-To | abuse@panix.com |
| NNTP-Posting-Date | Tue, 2 Dec 2014 22:52:27 +0000 (UTC) |
| User-Agent | nn/6.7.3 |
| Xref | csiph.com comp.lang.python:81819 |
Show key headers only | View raw
In <a1a70942-6740-4de5-b41e-57a71fb36910@googlegroups.com> Uzoma Ojemeni <uojemeni@gmail.com> writes:
> I am new to Python - a few days old - and I would appreciate some help.
> I want write a python code to parse the below XML as below:-
> ServingCell----------NeighbourCell
> L41_NBR3347_1----------L41_NBR3347_2
> L41_NBR3347_1----------L41_NBR3347_3
> L41_NBR3347_1----------L41_NBR3349_1
> L41_NBR3347_1----------L41_NBREA2242_1
> <LteCell id="L41_NBR3347_1">
> <attributes>
> <absPatternInfoTdd><unset/></absPatternInfoTdd>
> <additionalSpectrumEmission>1</additionalSpectrumEmission>
> <additionalSpectrumEmissionList><unset/></additionalSpectrumEmissionList>
> <LteSpeedDependentConf id="0">
> <attributes>
> <tReselectionEutraSfHigh>lDot0</tReselectionEut
> <tReselectionEutraSfMedium>lDot0</tReselectionE
> </attributes>
> </LteSpeedDependentConf>
> <LteNeighboringCellRelation id="L41_NBR3347_2">
> <attributes>
> <absPatternInfo><unset/></absPatternInfo>
> </LteNeighboringCellRelation>
> <LteNeighboringCellRelation id="L41_NBR3347_3">
> <attributes>
> <absPatternInfo><unset/></absPatternInfo>
> </LteNeighboringCellRelation>
> <LteNeighboringCellRelation id="L41_NBR3349_1">
> <attributes>
> <absPatternInfo><unset/></absPatternInfo>
> </LteNeighboringCellRelation>
> <LteNeighboringCellRelation id="L41_NBREA2242_1">
> <attributes>
> <absPatternInfo><unset/></absPatternInfo>
> <absPatternInfoTdd><unset/></absPatternInfoTdd>
In plain English, it looks like you want to do this:
1. Print a header.
2. For each <LteCell> element:
3. Find the child <attributes> element.
4. For each child <LteNeighboringCellRelation> element:
5. Print the "id" attributes of the <LteCell> element and the
<LteNeighboringCellRelation> element.
Translated to python, that would look something like this:
# import the xml library code
import xml.etree.ElementTree as ET
# load your XML file
tree = ET.parse('cells.xml')
# get the root element
root = tree.getroot()
# print a header
print("ServingCell------NeighbourCell")
# find each <LteCell> child element
for serving_cell in root.findall('LteCell'):
# find the <attributes> child element
attributes = serving_cell.find('attributes')
# find each <LteNeighboringCellRelation> child element
for neighbor in attributes.findall('LteNeighboringCellRelation'):
# print the id's of the serving and neighbor cells
print("%s------%s" % (serving_cell.attrib['id'], neighbor.attrib['id']))
--
John Gordon Imagine what it must be like for a real medical doctor to
gordon@panix.com watch 'House', or a real serial killer to watch 'Dexter'.
Back to comp.lang.python | Previous | Next — Previous in thread | Next in thread | Find similar | Unroll thread
Parsing XML Using XPATH for Python Uzoma Ojemeni <uojemeni@gmail.com> - 2014-12-02 14:13 -0800
Re: Parsing XML Using XPATH for Python John Gordon <gordon@panix.com> - 2014-12-02 22:52 +0000
Re: Parsing XML Using XPATH for Python Uzoma Ojemeni <uojemeni@gmail.com> - 2014-12-06 02:57 -0800
Re: Parsing XML Using XPATH for Python dieter <dieter@handshake.de> - 2014-12-03 07:59 +0100
csiph-web