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Re: strtotime() not able to handle 04/29 correctly???

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On 2/29/2012 1:41 PM, cerr wrote:
> Hi,
>
> I calculate the amount of days between two dates like this:
>
> 			$start = strtotime($_SESSION['sdate']);
> 			$end = strtotime($_SESSION['hdate']);
> 			echo ($end - $start);
> 			$duration = ($end - $start) / 3600 /24;
> 			$duration+=1; //plus one day
> 			echo " The ad will show for ".$duration." day(s)<br/>";
>
> Which generally works fine but things seem to mess up when I have a
> start sdate of 2012-02-29 and an hdate of 2012-04-01. I get a duration
> of: 32.9583333333
> Why is this? That's messing up my calculations. Is there a better way
> to do this?
>
> Thanks!
> Ron

Daylight savings time.

-- 
==================
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Jerry Stuckle
JDS Computer Training Corp.
jstucklex@attglobal.net
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Thread

strtotime() not able to handle 04/29 correctly??? cerr <ron.eggler@gmail.com> - 2012-02-29 10:41 -0800
  Re: strtotime() not able to handle 04/29 correctly??? "Peter H. Coffin" <hellsop@ninehells.com> - 2012-02-29 14:19 -0600
  Re: strtotime() not able to handle 04/29 correctly??? Jerry Stuckle <jstucklex@attglobal.net> - 2012-02-29 16:21 -0500
  Re: strtotime() not able to handle 04/29 correctly??? Doug Miller <doug_at_milmac_dot_com@example.com> - 2012-02-29 23:24 +0000
    Re: strtotime() not able to handle 04/29 correctly??? Eli the Bearded <*@eli.users.panix.com> - 2012-03-01 00:25 +0000
      Re: strtotime() not able to handle 04/29 correctly??? The Natural Philosopher <tnp@invalid.invalid> - 2012-03-01 00:46 +0000
      Re: strtotime() not able to handle 04/29 correctly??? Doug Miller <doug_at_milmac_dot_com@example.com> - 2012-03-01 01:28 +0000

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