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Re: ArrayObject - copy or reference

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Jo Schulze schrieb:

>> $array = array( 1, 2, 3 );
>> $obj = new ArrayObject( $array );
>> $obj[0] = 42;
>> echo $array[0];
>>
>> With PHP 5.2.0 this prints 42, with PHP 5.2.4 however, I get 1

> With PHP5.3.7rc this prints 42 which I would expect.

No it doesn't. I just installed PHP 5.3.7RC5 to test it. It prints 1.

> The line
> $obj[0] = 42;
> overwites the value with hash key 0 

It overwrites the value with hash key 0 in *$obj*. But it should not 
modify *$array*.

> I see no bug here.

There has definitely been a change in behaviour somewhere between 5.2.0 
and 5.2.4. And that should be documented somewhere.

Greetings,
Thomas

-- 
Ce n'est pas parce qu'ils sont nombreux à avoir tort qu'ils ont raison!
(Coluche)

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Thread

ArrayObject - copy or reference Thomas Mlynarczyk <thomas@mlynarczyk-webdesign.de> - 2011-08-08 19:28 +0200
  Re: ArrayObject - copy or reference Jo Schulze <antispam@feuersee.de> - 2011-08-17 00:03 +0200
    Re: ArrayObject - copy or reference Thomas Mlynarczyk <thomas@mlynarczyk-webdesign.de> - 2011-08-18 13:48 +0200
      Re: ArrayObject - copy or reference Jerry Stuckle <jstucklex@attglobal.net> - 2011-08-18 13:54 -0400
        Re: ArrayObject - copy or reference Thomas Mlynarczyk <thomas@mlynarczyk-webdesign.de> - 2011-08-18 20:44 +0200
          Re: ArrayObject - copy or reference Jerry Stuckle <jstucklex@attglobal.net> - 2011-08-18 19:26 -0400

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