Re: implode() order?

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From	Thomas 'PointedEars' Lahn <PointedEars@web.de>
Reply-To	Thomas 'PointedEars' Lahn <php@PointedEars.de>
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Date	Tue, 20 Dec 2011 02:55:49 +0100
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Subject	Re: implode() order?
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Mike wrote:

> Thanks... suppose the keys are not in a sortable order, like this:
> 
> $toImplode = Array(
>   "second" = "Second",
>   "fourth" = "Fourth",
>   "third" = "Third",
>   "first" = "First"
> );

This is not PHP code.
 
> Or would I need to simply:
> 
> echo $toImplode["first"] . $toImplode["second"]; // etc.

No, aside from u(k)sort() you can use a loop to build a new array:

  $a = array();

  foreach (array('first', 'second', 'third', 'fourth') as $key)
  {
    $a[] = $toImplode[$key];
  }

  echo implode(',', $a);


PointedEars
-- 
Prototype.js was written by people who don't know javascript for people
who don't know javascript. People who don't know javascript are not
the best source of advice on designing systems that use javascript.
  -- Richard Cornford, cljs, <f806at$ail$1$8300dec7@news.demon.co.uk>

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Thread

implode() order? Mike <mpearl1@gmail.com> - 2011-12-19 12:13 -0800
  Re: implode() order? Mike <mpearl1@gmail.com> - 2011-12-19 12:15 -0800
  Re: implode() order? Thomas Mlynarczyk <thomas@mlynarczyk-webdesign.de> - 2011-12-19 21:23 +0100
    Re: implode() order? Mike <mpearl1@gmail.com> - 2011-12-19 12:36 -0800
      Re: implode() order? Jerry Stuckle <jstucklex@attglobal.net> - 2011-12-19 16:15 -0500
        Re: implode() order? Mike <mpearl1@gmail.com> - 2011-12-19 13:30 -0800
        Re: implode() order? Thomas Mlynarczyk <thomas@mlynarczyk-webdesign.de> - 2011-12-19 23:47 +0100
          Re: implode() order? Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2011-12-20 02:59 +0100
            Re: implode() order? Jerry Stuckle <jstucklex@attglobal.net> - 2011-12-19 22:34 -0500
      Re: implode() order? Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2011-12-20 02:55 +0100

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