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Groups > comp.lang.javascript > #23816
| From | Andreas Bergmaier <andber93@web.de> |
|---|---|
| Newsgroups | comp.lang.javascript |
| Subject | Re: Defining functions in JavaScript |
| Date | 2014-04-07 18:00 +0200 |
| Organization | albasani.net |
| Message-ID | <lhui34$v6e$1@news.albasani.net> (permalink) |
| References | <1d82e037-4811-4a45-9668-985bdac67e45@googlegroups.com> |
AbdulFattah Popoola schrieb:
> issues developers should know about when using the various styles.
You haven't named http://kangax.github.io/nfe/ though?
> http://abdulapopoola.com/2014/04/03/defining-javascript-functions/
>
> Kindly post your feedback.
Some inaccurracies/mistakes:
* "Creating a function expression is easy: just declare a function where
the parser expects an expression and it automatically becomes a function
expression."
The term "declare" might be confusing here, it also indicates a name
which is optional for function expressions.
* "Function expressions are essential to achieve functional programming
concepts like currying, partials in JavaScript."
They are a fundamental part in the expressiveness of JavaScript, but
they're not *necessary* for functional programming. You could do
everything with function declarations only.
* "The last way is to use the Function keyword itself, this constructs a
function object and returns it."
No. The "function" keyword is what opens a function declaration or
function expression, you are referring to the "Function" *constructor*
function here. It might be a built-in global, but it's not a keyword.
* "the function body has to be parsed every time it is called."
A body isn't called, a function is. Because of that, the statement is
confusing; you should emphasize that the function body only needs to be
parsed when the Function constructor is called, not every time when the
resulting function is called and the body is executed.
* "And there are potential risks from malicious agents"
Those come from *unsafe* construction of dynamic code strings, not from
using Function() in general.
* "However for function expressions, the variable declaration is hoisted"
Not all function expressions appear inside a variable initialisation.
* if(true) {
//function expression because
//it is not a source element
function baz() {};
}
Nope, that's a syntax error. Expression statements must not begin with
the function keyword. See
http://kangax.github.io/nfe/#function-declarations-in-blocks for more
information
* "Here are some more examples of queer ways to create functions:"
eval('f("eval")');
setTimeout('f("timeout")',1000);
Those aren't really creating function objects, they're just evaling
code. You could however do
var f = eval("(function(str) { alert(str); })");
Regards,
Bergi
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Defining functions in JavaScript AbdulFattah Popoola <abdulapopoola@gmail.com> - 2014-04-06 08:19 -0700
Re: Defining functions in JavaScript Hans-Georg Michna <hans-georgNoEmailPlease@michna.com> - 2014-04-07 08:58 +0200
Re: Defining functions in JavaScript "Evertjan." <exxjxw.hannivoort@inter.nl.net> - 2014-04-07 13:43 +0200
Re: Defining functions in JavaScript Andreas Bergmaier <andber93@web.de> - 2014-04-07 18:00 +0200
Re: Defining functions in JavaScript Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2014-04-07 19:26 +0200
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