Re: string.replace()

Newsgroups	comp.lang.javascript
Subject	Re: string.replace()
From	"Evertjan." <exxjxw.hannivoort@inter.nl.net>
References	<qiv5ub$i5$1@dont-email.me> <replace-20190814002416@ram.dialup.fu-berlin.de> <XnsAAAB68E927159eejj99@194.109.6.166> <qj1v5t$4q0$1@dont-email.me>
Date	2019-08-15 13:55 +0200
Message-ID	<XnsAAAC8DB5EBF18eejj99@194.109.6.166> (permalink)

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Martin Leese <please@see.Web.for.e-mail.INVALID> wrote on 14 Aug 2019 in 
comp.lang.javascript:

> Evertjan. wrote:
>> However, 
>> since there are other characters that produce a visible space,
>> like the tab charater for instance,
>> you possibly could prefer to use the \s for 'any spacelike character':
>> 
>> myString = myString.replace( /\s/g, '+' ));
> 
> The strings are mine (as opposed to user
> input) so either will do.  This suggestion
> is more general, and so more bullet proof,
> so I will use it.
> 
>> If you are unsure about using Regex,
>> replace() can also, in a simple way, be used without that:
>> 
>> myString = myString.replace( ' ', '+' ));
>> 
>> but then the /g for 'global' would not be there,
>> and only the first instance of a space would be replaced.
> 
> My original post explained that there can
> be more than one space, so I have to use a
> regular expression.

This is Usenet, not a helpdesk,
so responses go to the group,
and may exeed an original question.

> Thanks for your help.

It may be expedient for you to learn Regex syntax and methods,
and not depend on thes same of others.


-- 
Evertjan.
The Netherlands.
(Please change the x'es to dots in my emailaddress)

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string.replace() Martin Leese <please@see.Web.for.e-mail.INVALID> - 2019-08-13 14:18 -0600
  Re: string.replace() dr.j.r.stockton@gmail.com - 2019-08-13 14:52 -0700
    Re: string.replace() Martin Leese <please@see.Web.for.e-mail.INVALID> - 2019-08-14 15:36 -0600
  Re: string.replace() "Evertjan." <exxjxw.hannivoort@inter.nl.net> - 2019-08-14 10:18 +0200
    Re: string.replace() Martin Leese <please@see.Web.for.e-mail.INVALID> - 2019-08-14 15:41 -0600
      Re: string.replace() "Evertjan." <exxjxw.hannivoort@inter.nl.net> - 2019-08-15 13:55 +0200

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