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Re: Remove portion of string unless it contains variable

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Jason C wrote on 14 jul 2012 in comp.lang.javascript:

> On Friday, July 13, 2012 7:27:09 PM UTC-4, Jason C wrote:
>> b = b.replace(/<img.*?src=["']*(.*?)["'}*.*?>/gi, '');
> 
> Type; that should have been a square after "', not a curly:
> 
> b = b.replace(/<img.*?src=["']*(.*?)["']*.*?>/gi, '');

Try this:

b = b.replace(/<img.*?src=(["'])[^\1]+\1[^>]*>/gi, '');


\1 is replaced by the actual match of (["'])

[^\1]+ quoted url should be not empty

[^>]*> matches anything till and including the next >

-- 
Evertjan.
The Netherlands.
(Please change the x'es to dots in my emailaddress)

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Remove portion of string unless it contains variable Jason C <jwcarlton@gmail.com> - 2012-07-13 16:27 -0700
  Re: Remove portion of string unless it contains variable Jason C <jwcarlton@gmail.com> - 2012-07-13 17:51 -0700
    Re: Remove portion of string unless it contains variable "Evertjan." <exxjxw.hannivoort@inter.nl.net> - 2012-07-14 10:03 +0000
  Re: Remove portion of string unless it contains variable Mike Winter <usenet@michael-winter.me.invalid> - 2012-07-16 01:06 +0100

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