Groups | Search | Server Info | Keyboard shortcuts | Login | Register [http] [https] [nntp] [nntps]

Groups > comp.lang.javascript > #34645

Re: DATA Structure one last time

Show all headers | View raw

Den tisdag 23 januari 2018 kl. 14:38:22 UTC+1 skrev Jonas Thörnvall:
> Den tisdag 23 januari 2018 kl. 14:18:59 UTC+1 skrev Jonas Thörnvall:
> > Den tisdag 23 januari 2018 kl. 10:22:22 UTC+1 skrev Jonas Thörnvall:
> > > Den tisdag 23 januari 2018 kl. 06:36:34 UTC+1 skrev Jonas Thörnvall:
> > > > Den måndag 22 januari 2018 kl. 17:32:41 UTC+1 skrev John G Harris:
> > > > > On Mon, 22 Jan 2018 04:32:00 -0800 (PST), Jonas Thörnvall
> > > > > <jonas.thornvall@gmail.com> wrote:
> > > > > 
> > > > >   <snip>
> > > > > >The syntax "it is always the syntax" 
> > > > > >
> > > > > >And honestly i can not see any reason why 
> > > > > >
> > > > > >track[m].midiMess[n].time=whatever 
> > > > > >
> > > > > >Would be equivalent to push "assign a value to object [n] because ones it created that is how you can assign it a new value.
> > > > > 
> > > > >   track[m].midiMess
> > > > > is an array object.
> > > > > 
> > > > >   track[m].midiMess[n]
> > > > > is an element of that array. 
> > > > > 
> > > > > IF you have put a message object into that element, by doing something
> > > > > like
> > > > >   track[m].midiMess[n] = { /*a message object*/ };
> > > > > then 
> > > > >   track[m].midiMess[n].time
> > > > > is a property of that message object. You can read from and write to
> > > > > it.
> > > > > 
> > > > > BUT if you have never put anything into that element then the element
> > > > > doesn't have properties (it's not an object; it's undefined).
> > > > > 
> > > > > 
> > > > > You don't have to use push. You could do it the old-fashioned way :
> > > > >   var size = track[m].midiMess.length;
> > > > >   track[m].midiMess[size+1] = { /*Object you want to add*/ };
> > > > > That's all that push does.
> > > > 
> > > > So track[m].midiMess[n] would have worked afterall, fuck now i get even more tired.
> > > > So it was just the curly paragraphs missing, fuck you people really evil LoL
> > > > No i mean it you are evil, anal anal retentive.
> > > >  
> > > > > 
> > > > > >I probably should do it in a more object oriented way set all the properties at once and not one at a time, but yet again i do not know the syntax.
> > > > > 
> > > > > "all the properties at once"! There's thousands of them, you said.
> > > > > 
> > > > > >I could guess 
> > > > > >track[m].midiMess[n]={time=clock,data0=mess0,data1=mess1,data2=mess2};
> > > > > >Is that correct or I should probably use colons?
> > > > > >But again it is not easy to guess the syntax to assign a subarray values, because that is what one do when one can not find appropriate examples.
> > > > > 
> > > > >   track[m].midiMess[n]
> > > > >   = {time:clock, data0:mess0, data1:mess1, data2:mess2};
> > > > > 
> > > > > An appropriate example :
> > > > > 
> > > > >   var arr = [];  // An empty array
> > > > >     // ...
> > > > >   arr[5] = {first:"alpha", second:"beta"};  
> > > > >     // Element 5 now holds an object
> > > > > 
> > > > >   John
> > > > 
> > > > Thank's John great Job!!! I think i save it until i forget the syntax next time.
> > > > There is teacher material in you, for sure!!!
> > > > 
> > > > Don't mind about my comments, they are more a sign of my shortcomings then yours.
> > > 
> > > I've adjusted the program to the new structure. And now i am onto downmix tracks  "to an omni track zero" And i do it the old fashioned way reading over the element values from one array object to track zero. One track at a time and then sort track zero.
> > > 
> > > But of course if javascript offer to copy the track right of, to track zero that would be preferable and i read about assign.
> > > 
> > > Example assign i found.
> > > const object1 = {
> > >   a: 1,
> > >   b: 2,
> > >   c: 3
> > > };
> > > const object2 = Object.assign({}, object1);
> > > console.log(object2.c);
> > > // expected output: 3
> > > 
> > > The examples always the simplest general case so it is so hard to see if they apply.
> > > 
> > > And i guess since my tracks object is an array, if i try to merge many tracks downto one they will simply overwrite eachother, or? 
> > > 
> > > const allRules = Object.assign({}, obj1, obj2, obj3, etc);
> > > If those were tracks, would they not write overeachothers indexes?
> > > 
> > > I would like the tracks stacked one after eachother,"and then i can do my midiMess.sort()" but is that possible?
> > 
> > How can i wait until the code that read midiports? "promise?" resolved, before init is called. 
> > 
> > 
> > if (navigator.requestMIDIAccess) {
> >     navigator.requestMIDIAccess()
> >         .then(success, failure);
> > }
> > 
> > function failure () {
> >     console.error('No access to your midi devices.'+ + msg )
> > }
> > 
> > function success (midi) {
> >     mid=midi;
> >     inputs = midi.inputs.values();
> >     // inputs outputs are Iterators
> >     for (input = inputs.next(); input && !input.done; input = inputs.next()) {
> >          // each time there is a midi message call the onMIDIMessage function
> >         input.value.onmidimessage = onMIDIMessage;
> >     } 
> > 
> >     init();  //SHOULD WAIT TO THE MIDIPORTS FETCHED  
> > }
> 
> Well i try to understand promises but i fail.
> 
> new Promise(function(success,failure) {
>         navigator.requestMIDIAccess();
> }).then(function() {
>    init();
> })
> 
> function failure () {
>     console.error('No access to your midi devices.'+ + msg )
> }
> 
> function success (midi) {
>     mid=midi;
>     inputs = midi.inputs.values();
>     // inputs outputs are Iterators
>     for (input = inputs.next(); input && !input.done; input = inputs.next()) {
>          // each time there is a midi message call the onMIDIMessage function
>         input.value.onmidimessage = onMIDIMessage;
>     } 
> }

Tried this one to
new Promise(function(success,failure) {
        navigator.requestMIDIAccess();
}).then(function(init) {
  
})

Back to comp.lang.javascript | Previous | Next — Previous in thread | Next in thread | Find similar | Unroll thread

Thread

DATA Structure one last time Jonas Thörnvall <jonas.thornvall@gmail.com> - 2018-01-21 01:50 -0800
  Re: DATA Structure one last time Jonas Thörnvall <jonas.thornvall@gmail.com> - 2018-01-21 02:09 -0800
    Re: DATA Structure one last time Jonas Thörnvall <jonas.thornvall@gmail.com> - 2018-01-21 03:35 -0800
      Re: DATA Structure one last time Jonas Thörnvall <jonas.thornvall@gmail.com> - 2018-01-21 04:10 -0800
        Re: DATA Structure one last time John G Harris <niam@jghnorth.org.uk.invalid> - 2018-01-21 18:04 +0000
          Re: DATA Structure one last time Jonas Thörnvall <jonas.thornvall@gmail.com> - 2018-01-21 20:03 -0800
            Re: DATA Structure one last time Jonas Thörnvall <jonas.thornvall@gmail.com> - 2018-01-21 20:07 -0800
            Re: DATA Structure one last time John G Harris <niam@jghnorth.org.uk.invalid> - 2018-01-22 10:47 +0000
              Re: DATA Structure one last time Jonas Thörnvall <jonas.thornvall@gmail.com> - 2018-01-22 04:32 -0800
                Re: DATA Structure one last time John G Harris <niam@jghnorth.org.uk.invalid> - 2018-01-22 16:32 +0000
                Re: DATA Structure one last time Jonas Thörnvall <jonas.thornvall@gmail.com> - 2018-01-22 21:36 -0800
                Re: DATA Structure one last time Jonas Thörnvall <jonas.thornvall@gmail.com> - 2018-01-23 01:22 -0800
                Re: DATA Structure one last time Jonas Thörnvall <jonas.thornvall@gmail.com> - 2018-01-23 05:18 -0800
                Re: DATA Structure one last time Jonas Thörnvall <jonas.thornvall@gmail.com> - 2018-01-23 05:38 -0800
                Re: DATA Structure one last time Jonas Thörnvall <jonas.thornvall@gmail.com> - 2018-01-23 05:44 -0800
                Re: DATA Structure one last time Jonas Thörnvall <jonas.thornvall@gmail.com> - 2018-01-23 06:07 -0800

csiph-web