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Re: OutputStream.write(int)

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Jan Burse wrote:

> At least we can say that 0x000000 and 0xFFFFFF must be ignored,
> otherwise the default implementation of write(byte[],..) gets
> broken:

I can see 0x000000, but not 0xffffff. And I'd be more suspicious
about <0 vs. >=0 than about intermediate bits.

> But an Outputstream might also overwrite this method, it is
> not a final method. But most likely we want:
> 
>       write(x)                      does the same as
>       write(new byte[]{(byte)x})
> 
> And the above invariant wouldn't hold if we were to interpret
> the upper 24-bits.

Good point. But I'd think that he who intentionally violates the
general contract might not care about that either.

-- 

"I'm a doctor, not a mechanic." Dr Leonard McCoy <mccoy@ncc1701.starfleet.fed>
"I'm a mechanic, not a doctor." Volker Borchert  <v_borchert@despammed.com>

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Thread

OutputStream.write(int) v_borchert@despammed.com (Volker Borchert) - 2016-06-05 22:54 +0000
  Re: OutputStream.write(int) Jan Burse <janburse@fastmail.fm> - 2016-06-06 01:45 +0200
    Re: OutputStream.write(int) v_borchert@despammed.com (Volker Borchert) - 2016-06-06 03:19 +0000
      Re: OutputStream.write(int) Jan Burse <janburse@fastmail.fm> - 2016-06-06 11:58 +0200
        Re: OutputStream.write(int) v_borchert@despammed.com (Volker Borchert) - 2016-06-06 15:51 +0000
  Re: OutputStream.write(int) Arne Vajhøj <arne@vajhoej.dk> - 2016-06-05 20:09 -0400
  Re: OutputStream.write(int) Kevin McMurtrie <mcmurtrie@pixelmemory.us> - 2016-06-05 19:38 -0700

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