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Re: Why is it called "default constructor"?

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From	Arne Vajhøj <arne@vajhoej.dk>
Newsgroups	comp.lang.java.programmer
Subject	Re: Why is it called "default constructor"?
Date	Sat, 4 Jun 2016 15:31:44 -0400
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On 6/4/2016 1:54 PM, Stefan Ram wrote:
> ram@zedat.fu-berlin.de (Stefan Ram) writes:
>> So, why is it called »default constructor«?
>
>   We can read this in the JLS:
>
> |The declaration:
> |
> |public class Point {
> |int x, y;
> |}
> |
> |is equivalent to the declaration:
> |
> |public class Point {
> |int x, y;
> |public Point() { super(); }
> |}
> |
> |where the default constructor is public because the class
> |Point is public.
>
>   So, it says that »public Point() { super(); }« is a »default
>   constructor« in the second class declaration.

I am not sure that it does.

I read it as that the implicit default constructor is public because
the class is public.

Not saying that the equivalent is a default constructor but explaining
why the equivalent is public.

Arne

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Re: Why is it called "default constructor"? Arne Vajhøj <arne@vajhoej.dk> - 2016-06-04 15:31 -0400

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