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Re: Why is it called "default constructor"?

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On 6/4/16 12:54 PM, Stefan Ram wrote:
> ram@zedat.fu-berlin.de (Stefan Ram) writes:
>> So, why is it called »default constructor«?
>
>   We can read this in the JLS:
>
> |The declaration:
> |
> |public class Point {
> |int x, y;
> |}
> |
> |is equivalent to the declaration:
> |
> |public class Point {
> |int x, y;
> |public Point() { super(); }
> |}
> |
> |where the default constructor is public because the class
> |Point is public.
>
>   So, it says that »public Point() { super(); }« is a »default
>   constructor« in the second class declaration.

The second class declaration is a fiction whose only purpose is to 
illustrate that the default constructor implicitly in the first class 
declaration has no parameters and has 'super();' as its only statement.

> Therefore,
>   »default constructor« can /not/ mean »used when no explicit
>   declaration is given«, because in the second class
>   declaration it /is/ given explicitly.

The second class declaration is not intended to be in a source file. The 
second class declaration is just in our imaginations.

--Mike Amling
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aGFzIG9uZSBvciBtb3JlIHBhcmFtZXRlcnMgbm90IHByZXNlbnQgaW4gdGhlIHNvdXJjZS4=

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Re: Why is it called "default constructor"? Mike Amling <mamling@chaff.us> - 2016-06-04 14:20 -0500

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