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Groups > comp.lang.java.programmer > #31802

Re: check if string has non-word characters

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On 6/16/2015 10:20 AM, mike wrote:
> Hi,
>
> String is not allowed to contain non-word characters. However it is ok with:
>
> 1.  = in as long it is not in the end or beginning of string.
> 2.  , as long as it is at the end of the string.

     Just typed in, untested:

	Pattern pattern = Pattern.compile("\\w[\\w=]*[\\w,]");

This isn't quite perfect, as it insists on at least two characters
(it won't match "x", for instance, though it will match "xx" or "x,").
Also, it matches "x=,", which your description permits but which might
not be what you intended.

     What is the larger problem you're trying to solve?  There might
be a better way to tackle it than to try to get the whole job done
with one super-regex.  As an old-line Netscape developer said,

	Some people, when confronted with a problem, think "I know,
	I'll use regular expressions."  Now they have two problems.

-- 
esosman@comcast-dot-net.invalid
"Don't be afraid of work. Make work afraid of you." -- TLM

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check if string has non-word characters mike <mikaelpetterson@hotmail.com> - 2015-06-16 07:20 -0700
  Re: check if string has non-word characters Eric Sosman <esosman@comcast-dot-net.invalid> - 2015-06-16 11:41 -0400
  Re: check if string has non-word characters Marcel Mueller <news.5.maazl@spamgourmet.org> - 2015-06-16 18:42 +0200
  Re: check if string has non-word characters Robert Klemme <shortcutter@googlemail.com> - 2015-06-16 22:58 +0200
  Re: check if string has non-word characters Daniel Pitts <newsgroup.nospam@virtualinfinity.net> - 2015-06-22 16:13 -0700

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