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Re: I don't understand why the following doesn't call Rectangle

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On Tuesday, December 13, 2016 at 11:06:46 AM UTC-5, cda...@gmail.com wrote:
> I think I have some serious misconceptions on how super() works. Also, is constructing a ComparableRectangle the same thing as constructing a ComparableRectangle object?

The values in the constructor is what you're missing.  When you specify a value without calling super you're calling the super constructor without the value.  Try the following test with and without the super.


public class TestClass1 {
     private int value = 0;
     public TestClass1() {
          
     }
     public TestClass1(int setValue) {
          value = setValue;
     }
     public int getValue() {
          return value;
     }
}
public class TestClass2 extends TestClass1 {
     public TestClass2(int setValue) {
          super(setValue);
     }
     public static void main(String[] args) {
          TestClass2 testMe = new TestClass2(6);
          System.out.println(testMe.getValue());
     }
}

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I don't understand why the following doesn't call Rectangle cdalten@gmail.com - 2016-12-13 07:42 -0800
  Re: I don't understand why the following doesn't call Rectangle Eric Douglas <e.d.programmer@gmail.com> - 2016-12-13 07:52 -0800
    Re: I don't understand why the following doesn't call Rectangle cdalten@gmail.com - 2016-12-13 08:06 -0800
      Re: I don't understand why the following doesn't call Rectangle Eric Douglas <e.d.programmer@gmail.com> - 2016-12-13 08:20 -0800
  Re: I don't understand why the following doesn't call Rectangle Eric Sosman <esosman@comcast-dot-net.invalid> - 2016-12-13 11:42 -0500
  Re: I don't understand why the following doesn't call Rectangle lewbloch@gmail.com - 2016-12-13 12:47 -0800
    Re: I don't understand why the following doesn't call Rectangle Manuel Collado <m.collado@domain.invalid> - 2016-12-14 19:13 +0100

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