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| From | Robert Klemme <shortcutter@googlemail.com> |
| Newsgroups | comp.lang.java.programmer |
| Subject | Re: BitSet vs boolean[] |
| Date | Fri, 18 Jul 2014 21:11:42 +0200 |
| Lines | 24 |
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On 18.07.2014 20:51, Roedy Green wrote: > In terms of minimising space, how big must a boolean array be before > it pays to use a BitSet? Well, a BitSet has these members - long[] - int - boolean If I'm not mistaken that yields sizeof(ref) + 8 * length + 4 + 4 = sizeof(ref) + 8 * (length + 1) bytes with length > 0 so at least sizeof(ref) + 16 bytes. I'd say worst case this is 8 + 16 = 24 bytes. Sinze a BitSet grows dramatically slower (on average 8 times) than a byte array if you add items that should be the max size. Of course, you can save even more memory by using a byte, short, int or long if you know the max set size is 8, 16, 32 or 64 bits and implement all the operations via bit logic. Kind regards robert
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BitSet vs boolean[] Roedy Green <see_website@mindprod.com.invalid> - 2014-07-18 11:51 -0700 Re: BitSet vs boolean[] Robert Klemme <shortcutter@googlemail.com> - 2014-07-18 21:11 +0200
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