Groups | Search | Server Info | Keyboard shortcuts | Login | Register [http] [https] [nntp] [nntps]
Groups > comp.lang.java.programmer > #33200
| Newsgroups | comp.lang.java.programmer |
|---|---|
| Date | 2015-11-25 13:33 -0800 |
| Message-ID | <46618f03-00af-47fe-affa-5e12b9a2f4cc@googlegroups.com> (permalink) |
| Subject | Generic cannot be applied |
| From | Philipp Kraus <philipp.kraus.flashpixx@gmail.com> |
Hello,
I have got these interface structure
public interface IVariable<T>
{
public T get();
public void set(T v);
}
public interface IOperator<T>
{
public IVariable<T> evaluate( IVariable<T> p );
}
and I implement this class
public class myOperator<T extends Number> implements Operator<T>
{
public IVariable<T> evaluate( IVariable<T> p )
{
p.set( new Double(p.get().doubleValue() + 1) ); <<<
return p;
}
}
The line with <<< create an compiler error and I need to cast the new Double to T, but I don't understand, why I must cast. The error message is "IVariable<T> cannot be applied". IMHO a Double inherit from Number and T extends a Number on myOperator class, so an explicit cast is not needed.
Can anybody explain, why I need a cast at the point <<< ?
Thanks
Phil
Back to comp.lang.java.programmer | Previous | Next — Next in thread | Find similar | Unroll thread
Generic cannot be applied Philipp Kraus <philipp.kraus.flashpixx@gmail.com> - 2015-11-25 13:33 -0800 Re: Generic cannot be applied Arne Vajhøj <arne@vajhoej.dk> - 2015-11-25 16:53 -0500 Re: Generic cannot be applied Eric Sosman <esosman@comcast-dot-net.invalid> - 2015-11-25 17:00 -0500 Re: Generic cannot be applied Joshua Cranmer 🐧 <Pidgeot18@verizon.invalid> - 2015-11-26 11:06 -0600
csiph-web