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.Re: Search for mapping solution

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> > Name - Number - Costs
> >
> > lines = [['fred','333','0,10'],['sam','444','1'],['fred','333','0,50']]
> >
> > Now I want to have it in a dictionary(name,costs)  Should look like
> > {'fred':'0,60' , 'sam':'1'}
> >
> > What's an elegant way to do it? I can use a lot of loops, but I assume, that
> > there is a better way of doing so.
> 
> lines = [['fred','333','0,10'],['sam','444','1'],['fred','333','0,50']]
> costs = {}
> for name, items, price in lines:
>      costs[name] = costs.setdefault(name, 0.0) +
> float(price.replace(',','.'))
> 
> print costs
> 
>  >>> {'fred': 0.59999999999999998, 'sam': 1.0}


[['fred','333','0,10'],['sam','444','1'],['fred','333','0,50']].
  reduce(Hash.new(0)){|hash,(name,_,cost)|
    hash[name] += cost.sub(',','.').to_f; hash}

  ===>
{"fred"=>0.6, "sam"=>1.0}


In Forth?


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.Re: Search for mapping solution "Robert L." <No_spamming@noWhere_7073.org> - 2017-04-20 06:58 +0000

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