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Which line(s) will compile ?

Started by	skybuck2000@hotmail.com
First post	2020-01-10 14:55 -0800
Last post	2020-01-11 00:14 +0000
Articles	2 — 2 participants

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  Which line(s) will compile ? skybuck2000@hotmail.com - 2020-01-10 14:55 -0800
    Re: Which line(s) will compile ? Ben Bacarisse <ben.usenet@bsb.me.uk> - 2020-01-11 00:14 +0000

#148915 — Which line(s) will compile ?

From	skybuck2000@hotmail.com
Date	2020-01-10 14:55 -0800
Subject	Which line(s) will compile ?
Message-ID	<8460a51c-be44-418a-bac9-5ccc69145c5f@googlegroups.com>

Since Pascal was invented by a C programmer, perhaps you C guys can help =D

Attempting to analyze the complexity of pascal's operators, [] . ignored:

A@@ := B@@;
A^@ := B@@;
A@^ := B@@;
A^^ := B@@;
A@@ := B^@;
A^@ := B^@;
A@^ := B^@;
A^^ := B^@;
A@@ := B@^;
A^@ := B@^;
A@^ := B@^;
A^^ := B@^;
A@@ := B^^;
A^@ := B^^;
A@^ := B^^;
A^^ := B^^;
A@@ := @B@;
A^@ := @B@;
A@^ := @B@;
A^^ := @B@;
A@@ := ^B@;
A^@ := ^B@;
A@^ := ^B@;
A^^ := ^B@;
A@@ := @B^;
A^@ := @B^;
A@^ := @B^;
A^^ := @B^;
A@@ := ^B^;
A^@ := ^B^;
A@^ := ^B^;
A^^ := ^B^;
A@@ := @@B;
A^@ := @@B;
A@^ := @@B;
A^^ := @@B;
A@@ := ^@B;
A^@ := ^@B;
A@^ := ^@B;
A^^ := ^@B;
A@@ := @^B;
A^@ := @^B;
A@^ := @^B;
A^^ := @^B;
A@@ := ^^B;
A^@ := ^^B;
A@^ := ^^B;
A^^ := ^^B;
@A@ := B@@;
^A@ := B@@;
@A^ := B@@;
^A^ := B@@;
@A@ := B^@;
^A@ := B^@;
@A^ := B^@;
^A^ := B^@;
@A@ := B@^;
^A@ := B@^;
@A^ := B@^;
^A^ := B@^;
@A@ := B^^;
^A@ := B^^;
@A^ := B^^;
^A^ := B^^;
@A@ := @B@;
^A@ := @B@;
@A^ := @B@;
^A^ := @B@;
@A@ := ^B@;
^A@ := ^B@;
@A^ := ^B@;
^A^ := ^B@;
@A@ := @B^;
^A@ := @B^;
@A^ := @B^;
^A^ := @B^;
@A@ := ^B^;
^A@ := ^B^;
@A^ := ^B^;
^A^ := ^B^;
@A@ := @@B;
^A@ := @@B;
@A^ := @@B;
^A^ := @@B;
@A@ := ^@B;
^A@ := ^@B;
@A^ := ^@B;
^A^ := ^@B;
@A@ := @^B;
^A@ := @^B;
@A^ := @^B;
^A^ := @^B;
@A@ := ^^B;
^A@ := ^^B;
@A^ := ^^B;
^A^ := ^^B;
@@A := B@@;
^@A := B@@;
@^A := B@@;
^^A := B@@;
@@A := B^@;
^@A := B^@;
@^A := B^@;
^^A := B^@;
@@A := B@^;
^@A := B@^;
@^A := B@^;
^^A := B@^;
@@A := B^^;
^@A := B^^;
@^A := B^^;
^^A := B^^;
@@A := @B@;
^@A := @B@;
@^A := @B@;
^^A := @B@;
@@A := ^B@;
^@A := ^B@;
@^A := ^B@;
^^A := ^B@;
@@A := @B^;
^@A := @B^;
@^A := @B^;
^^A := @B^;
@@A := ^B^;
^@A := ^B^;
@^A := ^B^;
^^A := ^B^;
@@A := @@B;
^@A := @@B;
@^A := @@B;
^^A := @@B;
@@A := ^@B;
^@A := ^@B;
@^A := ^@B;
^^A := ^@B;
@@A := @^B;
^@A := @^B;
@^A := @^B;
^^A := @^B;
@@A := ^^B;
^@A := ^^B;
@^A := ^^B;
^^A := ^^B;

Which of the lines above will actually compile ?

You may let A and B be any type you wish to make it compile ;)

Bye,
  Skybuck.

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#148918

From	Ben Bacarisse <ben.usenet@bsb.me.uk>
Date	2020-01-11 00:14 +0000
Message-ID	<87pnfqhmsn.fsf@bsb.me.uk>
In reply to	#148915

skybuck2000@hotmail.com writes:

> Since Pascal was invented by a C programmer,

Not possible.  C did not exists when Pascal was designed.

<cut>
-- 
Ben.

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Which line(s) will compile ?

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#148915 — Which line(s) will compile ?

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