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Initializing iterators to one past end() in for loops

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  Initializing iterators to one past end() in for loops Nikos Chantziaras <realnc@arcor.de> - 2011-04-14 00:38 +0300
    Re: Initializing iterators to one past end() in for loops Leigh Johnston <leigh@i42.co.uk> - 2011-04-13 22:46 +0100
    Re: Initializing iterators to one past end() in for loops Kai-Uwe Bux <jkherciueh@gmx.net> - 2011-04-13 23:48 +0200
      Re: Initializing iterators to one past end() in for loops Leigh Johnston <leigh@i42.co.uk> - 2011-04-13 22:50 +0100
        Re: Initializing iterators to one past end() in for loops Kai-Uwe Bux <jkherciueh@gmx.net> - 2011-04-14 00:23 +0200
          Re: Initializing iterators to one past end() in for loops Kai-Uwe Bux <jkherciueh@gmx.net> - 2011-04-14 00:32 +0200
            Re: Initializing iterators to one past end() in for loops Noah Roberts <dont@email.me> - 2011-04-13 17:16 -0700
              Re: Initializing iterators to one past end() in for loops Kai-Uwe Bux <jkherciueh@gmx.net> - 2011-04-14 05:57 +0200
                Re: Initializing iterators to one past end() in for loops Leigh Johnston <leigh@i42.co.uk> - 2011-04-14 14:29 +0100
                  Re: Initializing iterators to one past end() in for loops Kai-Uwe Bux <jkherciueh@gmx.net> - 2011-04-14 17:57 +0200
                    Re: Initializing iterators to one past end() in for loops Leigh Johnston <leigh@i42.co.uk> - 2011-04-14 17:56 +0100
                      Re: Initializing iterators to one past end() in for loops Kai-Uwe Bux <jkherciueh@gmx.net> - 2011-04-14 19:33 +0200
                Re: Initializing iterators to one past end() in for loops Noah Roberts <dont@email.me> - 2011-04-14 09:54 -0700
                  Re: Initializing iterators to one past end() in for loops Kai-Uwe Bux <jkherciueh@gmx.net> - 2011-04-14 20:08 +0200
    Re: Initializing iterators to one past end() in for loops gwowen <gwowen@gmail.com> - 2011-04-13 14:49 -0700
    Re: Initializing iterators to one past end() in for loops Sam <sam@email-scan.com> - 2011-04-13 16:58 -0500
    Re: Initializing iterators to one past end() in for loops Nikos Chantziaras <realnc@arcor.de> - 2011-04-14 01:07 +0300
      Re: Initializing iterators to one past end() in for loops Ian Collins <ian-news@hotmail.com> - 2011-04-14 10:12 +1200
      Re: Initializing iterators to one past end() in for loops gwowen <gwowen@gmail.com> - 2011-04-13 15:24 -0700
      Re: Initializing iterators to one past end() in for loops Paavo Helde <myfirstname@osa.pri.ee> - 2011-04-13 23:05 -0500
        Re: Initializing iterators to one past end() in for loops Ian Collins <ian-news@hotmail.com> - 2011-04-14 16:20 +1200
          Re: Initializing iterators to one past end() in for loops Paavo Helde <myfirstname@osa.pri.ee> - 2011-04-13 23:52 -0500
          Re: Initializing iterators to one past end() in for loops Jeff Flinn <TriumphSprint2000@hotmail.com> - 2011-04-14 07:49 -0400
        Re: Initializing iterators to one past end() in for loops Nikos Chantziaras <realnc@arcor.de> - 2011-04-14 21:45 +0300

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#3638

On 04/14/11 04:05 PM, Paavo Helde wrote:
> Nikos Chantziaras<realnc@arcor.de>  wrote in news:io56qc$cu8$1
> @news.grnet.gr:
>> Thanks for all the responses.  But I've made a mistake in my provided
>> example :-P  In the second loop, I'm using an std::list, not a vector:
>>
>>     std::list<int>  lst;
>>     typedef std::list<int>::iterator it_t;
>>     for (it_t i = lst.begin() + 1; i != lst.end(); ++i)
>>         // do something with *i
>>
>> (Converting some vectors to lists was the reason I came across this in
>> the first place.)
>>
>> I know it's not difficult to simply do something like:
>>
>>     it_t i = lst.begin();
>>     ++i;
>>     for ( ; i != lst.end(); ++i)
>>
>> but I was wondering whether there's some neat way to do that inside the
>> for header, so that 'i' will not stay in scope after the loop.
>
> std::list<int>  lst;
> typedef std::list<int>::iterator it_t;
> // populate list
>
> if (!lst.empty()) {
>      for (it_t i = std::next(lst.begin()); i != lst.end(); ++i) {

For those using C++0x compilers!

-- 
Ian Collins

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#3641

Ian Collins <ian-news@hotmail.com> wrote in news:90nb0sFeeiU14
@mid.individual.net:

> On 04/14/11 04:05 PM, Paavo Helde wrote:
>>      for (it_t i = std::next(lst.begin()); i != lst.end(); ++i) {
> 
> For those using C++0x compilers!

Right. It is working in VS2010 so I was sure this could not be something 
very advanced.

Cheers
Paavo

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#3661

Ian Collins wrote:
> On 04/14/11 04:05 PM, Paavo Helde wrote:
>> Nikos Chantziaras<realnc@arcor.de>  wrote in news:io56qc$cu8$1
>> @news.grnet.gr:
>>> Thanks for all the responses.  But I've made a mistake in my provided
>>> example :-P  In the second loop, I'm using an std::list, not a vector:
>>>
>>>     std::list<int>  lst;
>>>     typedef std::list<int>::iterator it_t;
>>>     for (it_t i = lst.begin() + 1; i != lst.end(); ++i)
>>>         // do something with *i
>>>
>>> (Converting some vectors to lists was the reason I came across this in
>>> the first place.)
>>>
>>> I know it's not difficult to simply do something like:
>>>
>>>     it_t i = lst.begin();
>>>     ++i;
>>>     for ( ; i != lst.end(); ++i)
>>>
>>> but I was wondering whether there's some neat way to do that inside the
>>> for header, so that 'i' will not stay in scope after the loop.
>>
>> std::list<int>  lst;
>> typedef std::list<int>::iterator it_t;
>> // populate list
>>
>> if (!lst.empty()) {
>>      for (it_t i = std::next(lst.begin()); i != lst.end(); ++i) {
> 
> For those using C++0x compilers!
> 

for (it_t i = boost::next(lst.begin()); i != lst.end(); ++i) {

For those with most any compiler!

Jeff

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#3715

On 04/14/2011 07:05 AM, Paavo Helde wrote:
> Nikos Chantziaras<realnc@arcor.de>  wrote in news:io56qc$cu8$1
> @news.grnet.gr:
>> Thanks for all the responses.  But I've made a mistake in my provided
>> example :-P  In the second loop, I'm using an std::list, not a vector:
>>
>>     std::list<int>  lst;
>>     typedef std::list<int>::iterator it_t;
>>     for (it_t i = lst.begin() + 1; i != lst.end(); ++i)
>>         // do something with *i
>>
>> (Converting some vectors to lists was the reason I came across this in
>> the first place.)
>>
>> I know it's not difficult to simply do something like:
>>
>>     it_t i = lst.begin();
>>     ++i;
>>     for ( ; i != lst.end(); ++i)
>>
>> but I was wondering whether there's some neat way to do that inside the
>> for header, so that 'i' will not stay in scope after the loop.
> [...]
>
> if (!lst.empty()) {
>      for (it_t i = std::next(lst.begin()); i != lst.end(); ++i) {
>          // do something
>      }
> }

Yep, that looks nicer!  It's C++0x, but seems to be supported well 
enough by now.

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