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Re: auto i:v as iterator

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On 2015-07-16 10:39, Ralf Goertz wrote:
> Hi,
>
> is it possible to have the new auto syntax for loops and get an iterator
> instead of a copy or a reference to the stored object itself? I would
> love to use the new syntax, but often I need to know what number in a
> vector the current object is. The following program doesn't compile.
>
> #include <vector>
> #include <iostream>
>
> int main() {
>      std::vector<int> v={47,11};
>      for (auto i:v) {
>          //std::cout<<i<<std::endl;
>          std::cout<<distance(i,v.begin())<<endl;
>      }
> 	return 0;
> }
>
>

If you have a reference to the element (auto&...), you can compute the 
difference between &i and &v[0].


Bo Persson

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auto i:v as iterator Ralf Goertz <me@myprovider.invalid> - 2015-07-16 10:39 +0200
  Re: auto i:v as iterator Bo Persson <bop@gmb.dk> - 2015-07-16 11:09 +0200
    Re: auto i:v as iterator Ralf Goertz <me@myprovider.invalid> - 2015-07-16 12:00 +0200
      Re: auto i:v as iterator Öö Tiib <ootiib@hot.ee> - 2015-07-16 05:17 -0700
        Re: auto i:v as iterator Ralf Goertz <me@myprovider.invalid> - 2015-07-16 15:47 +0200
          Re: auto i:v as iterator Öö Tiib <ootiib@hot.ee> - 2015-07-16 08:27 -0700
            Re: auto i:v as iterator Ralf Goertz <me@myprovider.invalid> - 2015-07-17 07:57 +0200
  Re: auto i:v as iterator bartekltg <bartekltg@gmail.com> - 2015-07-16 18:06 +0200
  Re: auto i:v as iterator "Alf P. Steinbach" <alf.p.steinbach+usenet@gmail.com> - 2015-07-17 23:18 +0200

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