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Groups > comp.graphics.apps.gnuplot > #2182

Re: Fit with "multi-part" function?

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On Wednesday, October 30, 2013 10:43:40 AM UTC+1, Karl wrote:
> delta0 does not appear in fnaux(), fn(), or Vth(), so you cannot fit
> "via delta0".
Well, at least not explicitly, but via b2
> b2=1./(3.*delta0-1)
> is not a function, so it does not get evaluated during fitting. You can
> declare
> b2(x)=1./(3.*x-1)
> and then replace all "b2" by "b2(alpha0)". Think it should work then.
I guess that would be b2(delta0). Anyway, I tried both
b2(x)=1./(3.*delta0-1),
calling b2(x) as b2(x) with x being a dummy variable, and
b2(delta0)=1./(3.*delta0-1),
calling it as b2(delta0) as you suggested, but the error remains the same.

Thomas

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Thread

Fit with "multi-part" function? trg818@gmail.com - 2013-10-29 16:57 -0700
  Re: Fit with "multi-part" function? Karl <mail.kfr@gmx.net> - 2013-10-30 10:43 +0100
    Re: Fit with "multi-part" function? trg818@gmail.com - 2013-10-30 06:44 -0700
      Re: Fit with "multi-part" function? Karl <mail.kfr@gmx.net> - 2013-10-30 16:18 +0100

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