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Groups > comp.databases.ms-sqlserver > #971 > unrolled thread
| Started by | Gerd Brix <gbrix@gmx.de> |
|---|---|
| First post | 2012-04-12 01:02 -0700 |
| Last post | 2012-04-12 04:33 -0700 |
| Articles | 6 — 3 participants |
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Database query -- how to? Gerd Brix <gbrix@gmx.de> - 2012-04-12 01:02 -0700
Re: Database query -- how to? bradbury9 <ray.bradbury9@gmail.com> - 2012-04-12 02:28 -0700
Re: Database query -- how to? Gerd Brix <gbrix@gmx.de> - 2012-04-12 02:38 -0700
Re: Database query -- how to? bradbury9 <ray.bradbury9@gmail.com> - 2012-04-12 04:10 -0700
Re: Database query -- how to? Erland Sommarskog <esquel@sommarskog.se> - 2012-04-12 11:10 +0000
Re: Database query -- how to? Gerd Brix <gbrix@gmx.de> - 2012-04-12 04:33 -0700
| From | Gerd Brix <gbrix@gmx.de> |
|---|---|
| Date | 2012-04-12 01:02 -0700 |
| Subject | Database query -- how to? |
| Message-ID | <67dc35a7-ea2e-4eb1-8bd4-7c7218c1e8e2@2g2000yqp.googlegroups.com> |
Hi all, I'm not too firm with writing SQL queries, thats why I'm asking here for help. There's a SQL Server Express with the following table: ID TIME ---------------- 1 8:00 1 7:45 2 6:00 3 5:00 2 7:59 What I need to find out is the last time entered for all given IDs. That means: ID TIME ---------------- 1 8:00 2 7:59 3 5:00 Can someone please help me with this? Thanks in advance! -gerd
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| From | bradbury9 <ray.bradbury9@gmail.com> |
|---|---|
| Date | 2012-04-12 02:28 -0700 |
| Message-ID | <33102916.190.1334222912192.JavaMail.geo-discussion-forums@vbbbg2> |
| In reply to | #971 |
El jueves, 12 de abril de 2012 10:02:09 UTC+2, Gerd Brix escribió: > Hi all, > > I'm not too firm with writing SQL queries, thats why I'm asking here > for help. > There's a SQL Server Express with the following table: > > ID TIME > ---------------- > 1 8:00 > 1 7:45 > 2 6:00 > 3 5:00 > 2 7:59 > > What I need to find out is the last time entered for all given IDs. > That means: > ID TIME > ---------------- > 1 8:00 > 2 7:59 > 3 5:00 > > Can someone please help me with this? > > Thanks in advance! > > -gerd In case the column TIME is DateTime type: Select max(TIME) from TableName If i is not DateTime, you will have to convert the data, heres a link to the documentation on Convert function and data types http://msdn.microsoft.com/es-es/library/ms187928.aspx
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| From | Gerd Brix <gbrix@gmx.de> |
|---|---|
| Date | 2012-04-12 02:38 -0700 |
| Message-ID | <14349368.675.1334223516823.JavaMail.geo-discussion-forums@yneo2> |
| In reply to | #972 |
Am Donnerstag, 12. April 2012 11:28:32 UTC+2 schrieb bradbury9: > El jueves, 12 de abril de 2012 10:02:09 UTC+2, Gerd Brix escribió: [...] > > There's a SQL Server Express with the following table: > > > > ID TIME > > ---------------- > > 1 8:00 > > 1 7:45 > > 2 6:00 > > 3 5:00 > > 2 7:59 > > > > What I need to find out is the last time entered for all given IDs. > > That means: > > ID TIME > > ---------------- > > 1 8:00 > > 2 7:59 > > 3 5:00 > > > > Can someone please help me with this? > > [...] > In case the column TIME is DateTime type: > Select max(TIME) from TableName > [...] Not really :-( This only delivers the latest entry. What I need is the latest entry for each ID. The example result shows this: 3 rows instead of only 1. -gerd
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| From | bradbury9 <ray.bradbury9@gmail.com> |
|---|---|
| Date | 2012-04-12 04:10 -0700 |
| Message-ID | <26142844.921.1334229036077.JavaMail.geo-discussion-forums@ynkf14> |
| In reply to | #973 |
El jueves, 12 de abril de 2012 11:38:36 UTC+2, Gerd Brix escribió: > Am Donnerstag, 12. April 2012 11:28:32 UTC+2 schrieb bradbury9: > > El jueves, 12 de abril de 2012 10:02:09 UTC+2, Gerd Brix escribió: > [...] > > > There's a SQL Server Express with the following table: > > > > > > ID TIME > > > ---------------- > > > 1 8:00 > > > 1 7:45 > > > 2 6:00 > > > 3 5:00 > > > 2 7:59 > > > > > > What I need to find out is the last time entered for all given IDs. > > > That means: > > > ID TIME > > > ---------------- > > > 1 8:00 > > > 2 7:59 > > > 3 5:00 > > > > > > Can someone please help me with this? > > > > [...] > > In case the column TIME is DateTime type: > > Select max(TIME) from TableName > > > [...] > > Not really :-( This only delivers the latest entry. What I need is the latest entry for each ID. The example result shows this: 3 rows instead of only 1. > > -gerd select [id], max(time) as latestTime from tableName group by [id]
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| From | Erland Sommarskog <esquel@sommarskog.se> |
|---|---|
| Date | 2012-04-12 11:10 +0000 |
| Message-ID | <XnsA033861654512Yazorman@127.0.0.1> |
| In reply to | #971 |
Gerd Brix (gbrix@gmx.de) writes: > There's a SQL Server Express with the following table: > > ID TIME > ---------------- > 1 8:00 > 1 7:45 > 2 6:00 > 3 5:00 > 2 7:59 > > What I need to find out is the last time entered for all given IDs. > That means: > ID TIME > ---------------- > 1 8:00 > 2 7:59 > 3 5:00 > > Can someone please help me with this? SELECT ID, MAX(Time) FROM tbl GROUP BY ID -- Erland Sommarskog, SQL Server MVP, esquel@sommarskog.se Books Online for SQL Server 2005 at http://www.microsoft.com/technet/prodtechnol/sql/2005/downloads/books.mspx Books Online for SQL Server 2000 at http://www.microsoft.com/sql/prodinfo/previousversions/books.mspx
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| From | Gerd Brix <gbrix@gmx.de> |
|---|---|
| Date | 2012-04-12 04:33 -0700 |
| Message-ID | <24542466.798.1334230420989.JavaMail.geo-discussion-forums@vbai14> |
| In reply to | #974 |
Thanks so much! Works like a charm. -gerd
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