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Groups > comp.lang.python > #29483
| References | <k3c9jb$2gr$1@ger.gmane.org> |
|---|---|
| Date | 2012-09-19 08:01 -0400 |
| Subject | Re: A little morning puzzle |
| From | Dwight Hutto <dwightdhutto@gmail.com> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.910.1348056073.27098.python-list@python.org> (permalink) |
> I have a list of dictionaries. They all have the same keys. I want to find the
> set of keys where all the dictionaries have the same values. Suggestions?
Here is my solution:
a = {}
a['dict'] = 1
b = {}
b['dict'] = 2
c = {}
c['dict'] = 1
d = {}
d['dict'] = 3
e = {}
e['dict'] = 1
x = [a,b,c,d,e]
collection_count = 0
for dict_key_search in x:
if dict_key_search['dict'] == 1:
collection_count += 1
print dict_key_search['dict']
Might be better ones though.
--
Best Regards,
David Hutto
CEO: http://www.hitwebdevelopment.com
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Re: A little morning puzzle Dwight Hutto <dwightdhutto@gmail.com> - 2012-09-19 08:01 -0400
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