Groups | Search | Server Info | Keyboard shortcuts | Login | Register [http] [https] [nntp] [nntps]


Groups > comp.lang.python > #29483

Re: A little morning puzzle

References <k3c9jb$2gr$1@ger.gmane.org>
Date 2012-09-19 08:01 -0400
Subject Re: A little morning puzzle
From Dwight Hutto <dwightdhutto@gmail.com>
Newsgroups comp.lang.python
Message-ID <mailman.910.1348056073.27098.python-list@python.org> (permalink)

Show all headers | View raw


> I have a list of dictionaries.  They all have the same keys.  I want to find the
> set of keys where all the dictionaries have the same values.  Suggestions?

Here is my solution:


a = {}
a['dict'] = 1

b = {}
b['dict'] = 2

c = {}
c['dict'] = 1

d = {}
d['dict'] = 3

e = {}
e['dict'] = 1


x = [a,b,c,d,e]
collection_count = 0

for dict_key_search in x:
	if dict_key_search['dict'] == 1:
		collection_count += 1
		print dict_key_search['dict']


Might be better ones though.


-- 
Best Regards,
David Hutto
CEO: http://www.hitwebdevelopment.com

Back to comp.lang.python | Previous | Next | Find similar | Unroll thread


Thread

Re: A little morning puzzle Dwight Hutto <dwightdhutto@gmail.com> - 2012-09-19 08:01 -0400

csiph-web