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Re: A little morning puzzle

Started byDwight Hutto <dwightdhutto@gmail.com>
First post2012-09-19 08:01 -0400
Last post2012-09-19 08:01 -0400
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  Re: A little morning puzzle Dwight Hutto <dwightdhutto@gmail.com> - 2012-09-19 08:01 -0400

#29483 — Re: A little morning puzzle

FromDwight Hutto <dwightdhutto@gmail.com>
Date2012-09-19 08:01 -0400
SubjectRe: A little morning puzzle
Message-ID<mailman.910.1348056073.27098.python-list@python.org>
> I have a list of dictionaries.  They all have the same keys.  I want to find the
> set of keys where all the dictionaries have the same values.  Suggestions?

Here is my solution:


a = {}
a['dict'] = 1

b = {}
b['dict'] = 2

c = {}
c['dict'] = 1

d = {}
d['dict'] = 3

e = {}
e['dict'] = 1


x = [a,b,c,d,e]
collection_count = 0

for dict_key_search in x:
	if dict_key_search['dict'] == 1:
		collection_count += 1
		print dict_key_search['dict']


Might be better ones though.


-- 
Best Regards,
David Hutto
CEO: http://www.hitwebdevelopment.com

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