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Re: User defined lexical scoping... can I do this?

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On 09/18/2012 10:50 PM, weissman.mark@gmail.com wrote:
> Well there's wired stuff like this:
> 
> In [1]: locals()["x"] = 5
> 
> In [2]: print x
> 5
> 

No, there isn't. Modifying the dictionary returned by locals() has no
effect.

>>> def f ():
...     locals()["x"] = 1
...     return x
...
>>> f ()
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "<stdin>", line 3, in f
NameError: global name 'x' is not defined
>>>
>>> locals()["x"] = 1
>>> x
1
>>> #this works because
... locals() is globals()
True
>>>

The exception is the case when local scope is identical to global scope.
In this case, locals() has globals() semantics.

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Thread

User defined lexical scoping... can I do this? porkfried <weissman.mark@gmail.com> - 2012-09-18 13:10 -0700
  Re: User defined lexical scoping... can I do this? Thomas Jollans <t@jollybox.de> - 2012-09-18 22:31 +0200
  Re: User defined lexical scoping... can I do this? weissman.mark@gmail.com - 2012-09-18 13:50 -0700
    Re: User defined lexical scoping... can I do this? Thomas Jollans <t@jollybox.de> - 2012-09-18 23:51 +0200
    Re: User defined lexical scoping... can I do this? Terry Reedy <tjreedy@udel.edu> - 2012-09-18 21:38 -0400
      Re: User defined lexical scoping... can I do this? Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2012-09-19 04:03 +0000
  Re: User defined lexical scoping... can I do this? Mark Lawrence <breamoreboy@yahoo.co.uk> - 2012-09-19 00:47 +0100

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