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Groups > comp.lang.python > #64617
| Date | 2014-01-23 09:30 -0600 |
|---|---|
| From | Tim Chase <python.list@tim.thechases.com> |
| Subject | Re: Initialise dictionary of dictionary |
| References | <f2f630c9-434c-43c1-bd80-4fadcc552e0a@googlegroups.com> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.5894.1390490976.18130.python-list@python.org> (permalink) |
On 2014-01-23 07:15, Ayushi Dalmia wrote:
> I need to initialise a dictionary of dictionary with float values.
> I do not know the size of the dictionary beforehand. How can we do
> that in Python --
Either
d = {}
or, if you want
from collections import defaultdict
d = defaultdict(float)
print(d["Hello"])
If you really do want a dict-of-dict that defaults to floats, you can
do
d = defaultdict(lambda: defaultdict(float))
print(d[3141]["Hello"])
-tkc
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Initialise dictionary of dictionary Ayushi Dalmia <ayushidalmia2604@gmail.com> - 2014-01-23 07:15 -0800
Re: Initialise dictionary of dictionary Tim Chase <python.list@tim.thechases.com> - 2014-01-23 09:30 -0600
Re: Initialise dictionary of dictionary Ayushi Dalmia <ayushidalmia2604@gmail.com> - 2014-01-23 21:42 -0800
Re:Initialise dictionary of dictionary Dave Angel <davea@davea.name> - 2014-01-23 10:34 -0500
Re: Initialise dictionary of dictionary Tim Chase <python.list@tim.thechases.com> - 2014-01-23 09:41 -0600
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