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Groups > comp.lang.python > #64661
| Newsgroups | comp.lang.python |
|---|---|
| Date | 2014-01-23 21:42 -0800 |
| References | <f2f630c9-434c-43c1-bd80-4fadcc552e0a@googlegroups.com> <mailman.5894.1390490976.18130.python-list@python.org> |
| Message-ID | <b5baa106-15a6-4e9a-bbfc-27c3224510ed@googlegroups.com> (permalink) |
| Subject | Re: Initialise dictionary of dictionary |
| From | Ayushi Dalmia <ayushidalmia2604@gmail.com> |
Thank you so much Tim. This is precisely what I wanted to do!
On Thursday, January 23, 2014 9:00:23 PM UTC+5:30, Tim Chase wrote:
> On 2014-01-23 07:15, Ayushi Dalmia wrote:
>
> > I need to initialise a dictionary of dictionary with float values.
>
> > I do not know the size of the dictionary beforehand. How can we do
>
> > that in Python --
>
>
>
> Either
>
>
>
> d = {}
>
>
>
> or, if you want
>
>
>
> from collections import defaultdict
>
> d = defaultdict(float)
>
> print(d["Hello"])
>
>
>
> If you really do want a dict-of-dict that defaults to floats, you can
>
> do
>
>
>
> d = defaultdict(lambda: defaultdict(float))
>
> print(d[3141]["Hello"])
>
>
>
> -tkc
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Initialise dictionary of dictionary Ayushi Dalmia <ayushidalmia2604@gmail.com> - 2014-01-23 07:15 -0800
Re: Initialise dictionary of dictionary Tim Chase <python.list@tim.thechases.com> - 2014-01-23 09:30 -0600
Re: Initialise dictionary of dictionary Ayushi Dalmia <ayushidalmia2604@gmail.com> - 2014-01-23 21:42 -0800
Re:Initialise dictionary of dictionary Dave Angel <davea@davea.name> - 2014-01-23 10:34 -0500
Re: Initialise dictionary of dictionary Tim Chase <python.list@tim.thechases.com> - 2014-01-23 09:41 -0600
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