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Groups > comp.lang.python > #18881
| From | Terry Reedy <tjreedy@udel.edu> |
|---|---|
| Subject | Re: stable object serialization to text file |
| Date | 2012-01-12 15:15 -0500 |
| References | <030AD516-2A52-411B-9A20-BD60DF8AE75B@me.com> <jemjde$98u$1@dough.gmane.org> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.4691.1326399385.27778.python-list@python.org> (permalink) |
On 1/12/2012 7:24 AM, Peter Otten wrote: > Máté Koch wrote: > >> I'm developing an app which stores the data in file system database. The >> data in my case consists of large python objects, mostly dicts, containing >> texts and numbers. The easiest way to dump and load them would be pickle, >> but I have a problem with it: I want to keep the data in version control, >> and I would like to use it as efficiently as possible. Is it possible to >> force pickle to store the otherwise unordered (e.g. dictionary) data in a >> kind of ordered way, so that if I dump a large dict, then change 1 tiny >> thing in it and dump again, the diff of the former and the new file will >> be minimal? >> >> If pickle is not the best choice for me, can you suggest anything else? >> (If there isn't any solution for it so far, I will write the module of >> course, but first I'd like to look around and make sure it hasn't been >> created yet.) > > Have you considered json? > > http://docs.python.org/library/json.html > > The encoder features a sort_keys flag which might help. If that does not do it for you, consider that a dict is a two-column table, with arbitrary structures in each column. Convert to list with sorted(somedict.items()). This is basically what json should do. Then write to a text stream, one line per key,value pair. Whether you put the text into an os file in a directory (a hierachical database ;-) or a text field in another database is up to you. Either way, diffs are easy. -- Terry Jan Reedy
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Re: stable object serialization to text file Terry Reedy <tjreedy@udel.edu> - 2012-01-12 15:15 -0500
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