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Groups > comp.lang.python > #93395
| Date | 2015-07-02 01:30 +0100 |
|---|---|
| From | MRAB <python@mrabarnett.plus.com> |
| Subject | Re: "normalizing" a value |
| References | <fd370a7b-ea6a-48e5-90f4-9d86b89a745e@googlegroups.com> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.229.1435797056.3674.python-list@python.org> (permalink) |
On 2015-07-02 01:12, bvdp wrote:
> Not sure what this is called (and I'm sure it's not normalize). Perhaps "scaling"?
>
> Anyway, I need to convert various values ranging from around -50 to 50 to an 0 to 12 range (this is part of a MIDI music program). I have a number of places where I do:
>
> while x < 0: x += 12
> while x >= 12: x -= 12
>
> Okay, that works. Just wondering if there is an easier (or faster) way to accomplish this.
>
That's called "modular arithmetic". Use the modulo operator, '%':
x = x % 12
or just:
x %= 12
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"normalizing" a value bvdp <bob@mellowood.ca> - 2015-07-01 17:12 -0700
Re: "normalizing" a value MRAB <python@mrabarnett.plus.com> - 2015-07-02 01:30 +0100
Re: "normalizing" a value Paul Rubin <no.email@nospam.invalid> - 2015-07-01 17:36 -0700
Re: "normalizing" a value Denis McMahon <denismfmcmahon@gmail.com> - 2015-07-02 01:06 +0000
Re: "normalizing" a value random832@fastmail.us - 2015-07-01 21:27 -0400
Re: "normalizing" a value bvdp <bob@mellowood.ca> - 2015-07-01 18:49 -0700
Re: "normalizing" a value random832@fastmail.us - 2015-07-01 22:23 -0400
Re: "normalizing" a value bvdp <bob@mellowood.ca> - 2015-07-01 19:41 -0700
Re: "normalizing" a value Dennis Lee Bieber <wlfraed@ix.netcom.com> - 2015-07-01 23:36 -0400
Re: "normalizing" a value bvdp <bob@mellowood.ca> - 2015-07-02 10:03 -0700
Re: "normalizing" a value Steven D'Aprano <steve@pearwood.info> - 2015-07-02 12:15 +1000
Re: "normalizing" a value bvdp <bob@mellowood.ca> - 2015-07-01 19:42 -0700
Re: "normalizing" a value Mark Lawrence <breamoreboy@yahoo.co.uk> - 2015-07-02 05:41 +0100
Re: "normalizing" a value Skip Montanaro <skip.montanaro@gmail.com> - 2015-07-02 10:05 -0500
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