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Re: "normalizing" a value

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Date Thu, 02 Jul 2015 01:30:45 +0100
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On 2015-07-02 01:12, bvdp wrote:
> Not sure what this is called (and I'm sure it's not normalize). Perhaps "scaling"?
>
> Anyway, I need to convert various values ranging from around -50 to 50 to an 0 to 12 range (this is part of a MIDI music program). I have a number of places where I do:
>
>     while x < 0: x += 12
>     while x >= 12: x -= 12
>
> Okay, that works. Just wondering if there is an easier (or faster) way to accomplish this.
>
That's called "modular arithmetic". Use the modulo operator, '%':

     x = x % 12

or just:

     x %= 12

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Thread

"normalizing" a value bvdp <bob@mellowood.ca> - 2015-07-01 17:12 -0700
  Re: "normalizing" a value MRAB <python@mrabarnett.plus.com> - 2015-07-02 01:30 +0100
  Re: "normalizing" a value Paul Rubin <no.email@nospam.invalid> - 2015-07-01 17:36 -0700
  Re: "normalizing" a value Denis McMahon <denismfmcmahon@gmail.com> - 2015-07-02 01:06 +0000
  Re: "normalizing" a value random832@fastmail.us - 2015-07-01 21:27 -0400
    Re: "normalizing" a value bvdp <bob@mellowood.ca> - 2015-07-01 18:49 -0700
      Re: "normalizing" a value random832@fastmail.us - 2015-07-01 22:23 -0400
        Re: "normalizing" a value bvdp <bob@mellowood.ca> - 2015-07-01 19:41 -0700
      Re: "normalizing" a value Dennis Lee Bieber <wlfraed@ix.netcom.com> - 2015-07-01 23:36 -0400
        Re: "normalizing" a value bvdp <bob@mellowood.ca> - 2015-07-02 10:03 -0700
  Re: "normalizing" a value Steven D'Aprano <steve@pearwood.info> - 2015-07-02 12:15 +1000
    Re: "normalizing" a value bvdp <bob@mellowood.ca> - 2015-07-01 19:42 -0700
  Re: "normalizing" a value Mark Lawrence <breamoreboy@yahoo.co.uk> - 2015-07-02 05:41 +0100
  Re: "normalizing" a value Skip Montanaro <skip.montanaro@gmail.com> - 2015-07-02 10:05 -0500

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