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Groups > comp.lang.python > #109811
| From | Tim Chase <python.list@tim.thechases.com> |
|---|---|
| Newsgroups | comp.lang.python |
| Subject | Re: fast dictionary initialization |
| Date | 2016-06-10 18:20 -0500 |
| Message-ID | <mailman.148.1465613257.2306.python-list@python.org> (permalink) |
| References | <d2ee0910-1635-431e-944c-c8b4167f10c5@googlegroups.com> <20160610182014.0a9182a9@bigbox.christie.dr> |
On 2016-06-10 14:07, maurice wrote:
> example:
> valuesList = [1,2,3]
> keysList = ['1','2','3']
>
> So the dictionary can basically convert string to int:
>
> dictionary = {'1':1, '2':2, '3':3}
A couple similar options:
The most straightforward translation of your description:
opt1 = dict(zip(keysList, valuesList))
print(opt1["2"])
And one where you generate the strings on the fly:
opt2 = dict((str(i), i) for i in range(1, 4))
print(opt2["2"])
And one where you use the int() function instead of a mapping because
the whole idea of storing a dict worth of string-numbers-to-numbers
seems somewhat silly to me:
print(int("2"))
-tkc
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fast dictionary initialization maurice <mauricioliveiraguarda@gmail.com> - 2016-06-10 14:07 -0700 Re: fast dictionary initialization Random832 <random832@fastmail.com> - 2016-06-10 17:15 -0400 Re: fast dictionary initialization Tim Chase <python.list@tim.thechases.com> - 2016-06-10 18:20 -0500
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