Path: csiph.com!fu-berlin.de!uni-berlin.de!not-for-mail
From: Tim Chase <python.list@tim.thechases.com>
Newsgroups: comp.lang.python
Subject: Re: fast dictionary initialization
Date: Fri, 10 Jun 2016 18:20:14 -0500
Lines: 32
Message-ID: <mailman.148.1465613257.2306.python-list@python.org>
References: <d2ee0910-1635-431e-944c-c8b4167f10c5@googlegroups.com> <20160610182014.0a9182a9@bigbox.christie.dr>
Mime-Version: 1.0
Content-Type: text/plain; charset=US-ASCII
Content-Transfer-Encoding: 7bit
In-Reply-To: <d2ee0910-1635-431e-944c-c8b4167f10c5@googlegroups.com>
Precedence: list
Xref: csiph.com comp.lang.python:109811

On 2016-06-10 14:07, maurice wrote:
> example:
> valuesList = [1,2,3]
> keysList   = ['1','2','3']
> 
> So the dictionary can basically convert string to int:
> 
> dictionary = {'1':1, '2':2, '3':3}

A couple similar options:


The most straightforward translation of your description:

  opt1 = dict(zip(keysList, valuesList))
  print(opt1["2"])

And one where you generate the strings on the fly:

  opt2 = dict((str(i), i) for i in range(1, 4))
  print(opt2["2"])

And one where you use the int() function instead of a mapping because
the whole idea of storing a dict worth of string-numbers-to-numbers
seems somewhat silly to me:

  print(int("2"))

-tkc