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Re: ideal gas law - pressure and mass question

From Christopher Howard <christopher@librehacker.com>
Newsgroups sci.physics
Subject Re: ideal gas law - pressure and mass question
Date 2026-04-18 08:45 -0800
Organization A noiseless patient Spider
Message-ID <87pl3wusig.fsf@librehacker.com> (permalink)
References <87a4v1wf3o.fsf@librehacker.com> <10rua1g$1jdul$1@gwaiyur.mb-net.net>

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Thomas 'PointedEars' Lahn <PointedEars@web.de> writes:

> True.  With constant volume, the temperature will increase according to
>
>   ∆Q = m c_V ∆T  ⇔  ∆T = ∆Q/(m c_V),
>
> where Q is heat; m is the mass of the gas, and c_V is its specific heat
> capacity at constant volume.
>
> And since the equation of state (EOS) of an ideal gas, also known as "Ideal
> Gas Law", can be written
>
>   p V = N k_B T,
>
> if the volume V and number of particles N are constant, and the absolute
> temperature T increases, then the pressure p will increase proportionally to
> the change in T, therefore to the change in Q:
>
>   ∆p = (N k_B/V) ∆T ∝ ∆T ∝ ∆Q.
>

Intuitively, it makes sense to me that if I have a greater mass of gas
involved, therefore the pressure will increase more slowly with the same
amount of applied heat.

I can see certainly that temperature will increase more slowly, because,
as you point out, ∆T = ∆Q/(m c_V).

However, in the equation p V = N k_B T, the number of particles, N, does
change with an increase in mass, correct? I think if we assumed we were
dealing with air, with a molar mass of about 30 g/mol, or 3x10⁻² kg/mol,
then the equation converts to this, correct?:

M = N × 3x10⁻² kg/mol
N = M / (3x10⁻² kg/mol)

Δp = (M / (3x10⁻² kg/mol)) × (R / V) × ΔT
Δp = (M / (3x10⁻² kg/mol)) × (R / V) × (∆Q / M c_air)

And therefore the mass terms (M) cancel out, correct...?

-- 
Christopher Howard

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Thread

ideal gas law - pressure and mass question Christopher Howard <christopher@librehacker.com> - 2026-04-17 11:39 -0800
  Re: ideal gas law - pressure and mass question Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2026-04-17 23:51 +0200
    Re: ideal gas law - pressure and mass question Christopher Howard <christopher@librehacker.com> - 2026-04-18 08:45 -0800
      Re: ideal gas law - pressure and mass question John Hasler <john@sugarbit.com> - 2026-04-18 14:02 -0500
      Re: ideal gas law - pressure and mass question ram@zedat.fu-berlin.de (Stefan Ram) - 2026-04-18 19:40 +0000
        Re: ideal gas law - pressure and mass question John Hasler <john@sugarbit.com> - 2026-04-18 15:29 -0500
        Re: ideal gas law - pressure and mass question ram@zedat.fu-berlin.de (Stefan Ram) - 2026-04-18 21:49 +0000
  Re: ideal gas law - pressure and mass question John Hasler <john@sugarbit.com> - 2026-04-17 16:22 -0500

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