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| From | Christopher Howard <christopher@librehacker.com> |
|---|---|
| Newsgroups | sci.physics |
| Subject | Re: ideal gas law - pressure and mass question |
| Date | 2026-04-18 08:45 -0800 |
| Organization | A noiseless patient Spider |
| Message-ID | <87pl3wusig.fsf@librehacker.com> (permalink) |
| References | <87a4v1wf3o.fsf@librehacker.com> <10rua1g$1jdul$1@gwaiyur.mb-net.net> |
Thomas 'PointedEars' Lahn <PointedEars@web.de> writes: > True. With constant volume, the temperature will increase according to > > ∆Q = m c_V ∆T ⇔ ∆T = ∆Q/(m c_V), > > where Q is heat; m is the mass of the gas, and c_V is its specific heat > capacity at constant volume. > > And since the equation of state (EOS) of an ideal gas, also known as "Ideal > Gas Law", can be written > > p V = N k_B T, > > if the volume V and number of particles N are constant, and the absolute > temperature T increases, then the pressure p will increase proportionally to > the change in T, therefore to the change in Q: > > ∆p = (N k_B/V) ∆T ∝ ∆T ∝ ∆Q. > Intuitively, it makes sense to me that if I have a greater mass of gas involved, therefore the pressure will increase more slowly with the same amount of applied heat. I can see certainly that temperature will increase more slowly, because, as you point out, ∆T = ∆Q/(m c_V). However, in the equation p V = N k_B T, the number of particles, N, does change with an increase in mass, correct? I think if we assumed we were dealing with air, with a molar mass of about 30 g/mol, or 3x10⁻² kg/mol, then the equation converts to this, correct?: M = N × 3x10⁻² kg/mol N = M / (3x10⁻² kg/mol) Δp = (M / (3x10⁻² kg/mol)) × (R / V) × ΔT Δp = (M / (3x10⁻² kg/mol)) × (R / V) × (∆Q / M c_air) And therefore the mass terms (M) cancel out, correct...? -- Christopher Howard
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ideal gas law - pressure and mass question Christopher Howard <christopher@librehacker.com> - 2026-04-17 11:39 -0800
Re: ideal gas law - pressure and mass question Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2026-04-17 23:51 +0200
Re: ideal gas law - pressure and mass question Christopher Howard <christopher@librehacker.com> - 2026-04-18 08:45 -0800
Re: ideal gas law - pressure and mass question John Hasler <john@sugarbit.com> - 2026-04-18 14:02 -0500
Re: ideal gas law - pressure and mass question ram@zedat.fu-berlin.de (Stefan Ram) - 2026-04-18 19:40 +0000
Re: ideal gas law - pressure and mass question John Hasler <john@sugarbit.com> - 2026-04-18 15:29 -0500
Re: ideal gas law - pressure and mass question ram@zedat.fu-berlin.de (Stefan Ram) - 2026-04-18 21:49 +0000
Re: ideal gas law - pressure and mass question John Hasler <john@sugarbit.com> - 2026-04-17 16:22 -0500
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