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Groups > comp.databases.ms-sqlserver > #973
| From | Gerd Brix <gbrix@gmx.de> |
|---|---|
| Newsgroups | comp.databases.ms-sqlserver |
| Subject | Re: Database query -- how to? |
| Date | 2012-04-12 02:38 -0700 |
| Organization | http://groups.google.com |
| Message-ID | <14349368.675.1334223516823.JavaMail.geo-discussion-forums@yneo2> (permalink) |
| References | <67dc35a7-ea2e-4eb1-8bd4-7c7218c1e8e2@2g2000yqp.googlegroups.com> <33102916.190.1334222912192.JavaMail.geo-discussion-forums@vbbbg2> |
Am Donnerstag, 12. April 2012 11:28:32 UTC+2 schrieb bradbury9: > El jueves, 12 de abril de 2012 10:02:09 UTC+2, Gerd Brix escribió: [...] > > There's a SQL Server Express with the following table: > > > > ID TIME > > ---------------- > > 1 8:00 > > 1 7:45 > > 2 6:00 > > 3 5:00 > > 2 7:59 > > > > What I need to find out is the last time entered for all given IDs. > > That means: > > ID TIME > > ---------------- > > 1 8:00 > > 2 7:59 > > 3 5:00 > > > > Can someone please help me with this? > > [...] > In case the column TIME is DateTime type: > Select max(TIME) from TableName > [...] Not really :-( This only delivers the latest entry. What I need is the latest entry for each ID. The example result shows this: 3 rows instead of only 1. -gerd
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Database query -- how to? Gerd Brix <gbrix@gmx.de> - 2012-04-12 01:02 -0700
Re: Database query -- how to? bradbury9 <ray.bradbury9@gmail.com> - 2012-04-12 02:28 -0700
Re: Database query -- how to? Gerd Brix <gbrix@gmx.de> - 2012-04-12 02:38 -0700
Re: Database query -- how to? bradbury9 <ray.bradbury9@gmail.com> - 2012-04-12 04:10 -0700
Re: Database query -- how to? Erland Sommarskog <esquel@sommarskog.se> - 2012-04-12 11:10 +0000
Re: Database query -- how to? Gerd Brix <gbrix@gmx.de> - 2012-04-12 04:33 -0700
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