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Re: Database query -- how to?

From Gerd Brix <gbrix@gmx.de>
Newsgroups comp.databases.ms-sqlserver
Subject Re: Database query -- how to?
Date 2012-04-12 02:38 -0700
Organization http://groups.google.com
Message-ID <14349368.675.1334223516823.JavaMail.geo-discussion-forums@yneo2> (permalink)
References <67dc35a7-ea2e-4eb1-8bd4-7c7218c1e8e2@2g2000yqp.googlegroups.com> <33102916.190.1334222912192.JavaMail.geo-discussion-forums@vbbbg2>

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Am Donnerstag, 12. April 2012 11:28:32 UTC+2 schrieb bradbury9:
> El jueves, 12 de abril de 2012 10:02:09 UTC+2, Gerd Brix  escribió:
[...]
> > There's a SQL Server Express with the following table:
> > 
> > ID     TIME
> > ----------------
> > 1       8:00
> > 1       7:45
> > 2       6:00
> > 3       5:00
> > 2       7:59
> > 
> > What I need to find out is the last time entered for all given IDs.
> > That means:
> > ID     TIME
> > ----------------
> > 1      8:00
> > 2      7:59
> > 3      5:00
> > 
> > Can someone please help me with this?
> > 
[...] 
> In case the column TIME is DateTime type:
> Select max(TIME) from TableName
> 
[...]

Not really :-(  This only delivers the latest entry. What I need is the latest entry for each ID. The example result shows this: 3 rows instead of only 1.

-gerd

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Thread

Database query -- how to? Gerd Brix <gbrix@gmx.de> - 2012-04-12 01:02 -0700
  Re: Database query -- how to? bradbury9 <ray.bradbury9@gmail.com> - 2012-04-12 02:28 -0700
    Re: Database query -- how to? Gerd Brix <gbrix@gmx.de> - 2012-04-12 02:38 -0700
      Re: Database query -- how to? bradbury9 <ray.bradbury9@gmail.com> - 2012-04-12 04:10 -0700
  Re: Database query -- how to? Erland Sommarskog <esquel@sommarskog.se> - 2012-04-12 11:10 +0000
    Re: Database query -- how to? Gerd Brix <gbrix@gmx.de> - 2012-04-12 04:33 -0700

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