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Groups > comp.databases.ms-sqlserver > #975

Re: Database query -- how to?

From bradbury9 <ray.bradbury9@gmail.com>
Newsgroups comp.databases.ms-sqlserver
Subject Re: Database query -- how to?
Date 2012-04-12 04:10 -0700
Organization http://groups.google.com
Message-ID <26142844.921.1334229036077.JavaMail.geo-discussion-forums@ynkf14> (permalink)
References <67dc35a7-ea2e-4eb1-8bd4-7c7218c1e8e2@2g2000yqp.googlegroups.com> <33102916.190.1334222912192.JavaMail.geo-discussion-forums@vbbbg2> <14349368.675.1334223516823.JavaMail.geo-discussion-forums@yneo2>

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El jueves, 12 de abril de 2012 11:38:36 UTC+2, Gerd Brix  escribió:
> Am Donnerstag, 12. April 2012 11:28:32 UTC+2 schrieb bradbury9:
> > El jueves, 12 de abril de 2012 10:02:09 UTC+2, Gerd Brix  escribió:
> [...]
> > > There's a SQL Server Express with the following table:
> > > 
> > > ID     TIME
> > > ----------------
> > > 1       8:00
> > > 1       7:45
> > > 2       6:00
> > > 3       5:00
> > > 2       7:59
> > > 
> > > What I need to find out is the last time entered for all given IDs.
> > > That means:
> > > ID     TIME
> > > ----------------
> > > 1      8:00
> > > 2      7:59
> > > 3      5:00
> > > 
> > > Can someone please help me with this?
> > > 
> [...] 
> > In case the column TIME is DateTime type:
> > Select max(TIME) from TableName
> > 
> [...]
> 
> Not really :-(  This only delivers the latest entry. What I need is the latest entry for each ID. The example result shows this: 3 rows instead of only 1.
> 
> -gerd

select [id], max(time) as latestTime from tableName group by [id]

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Thread

Database query -- how to? Gerd Brix <gbrix@gmx.de> - 2012-04-12 01:02 -0700
  Re: Database query -- how to? bradbury9 <ray.bradbury9@gmail.com> - 2012-04-12 02:28 -0700
    Re: Database query -- how to? Gerd Brix <gbrix@gmx.de> - 2012-04-12 02:38 -0700
      Re: Database query -- how to? bradbury9 <ray.bradbury9@gmail.com> - 2012-04-12 04:10 -0700
  Re: Database query -- how to? Erland Sommarskog <esquel@sommarskog.se> - 2012-04-12 11:10 +0000
    Re: Database query -- how to? Gerd Brix <gbrix@gmx.de> - 2012-04-12 04:33 -0700

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