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Groups > microsoft.public.sqlserver.programming > #31350

Ordering the columns in a pivot table

Newsgroups microsoft.public.sqlserver.programming
Date 2020-04-11 09:00 -0700
Message-ID <9c212941-b3a2-4f07-b29c-e8145580bbad@googlegroups.com> (permalink)
Subject Ordering the columns in a pivot table
From John Hall <foundarecord@gmail.com>

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I have a data table with these 3 columns 
SELECT [TestID],[ParameterID],[TextValue]
  FROM [ParameterEntries]

select TestID, [1] as Param1, [2] as Param2, [3] as Param3, [4] as Param4, [5] as Param5
from (select TestID, TextValue,
    row_number() over(partition by TestID order by ParameterID) rnk
  from ParameterEntries WHERE TestID = (SELECT TOP 1 TestID FROM Subgroups WHERE CharID = 502107)
) p
pivot(max(TextValue) for rnk in ([1], [2], [3], [4], [5])) piv

TestID  Param1          Param2  Param3  Param4  Param5
502014	20147338	3w	2.14	1.49	1.73

SELECT [PartID], [ParameterID], [PresentOrder]
  FROM [ParametersUsed]
  WHERE PartID = (SELECT PartID FROM CharList WHERE CharID = 502107)
  ORDER BY PresentOrder

TestID  ParameterID  PresentOrder
502014	154	     1
502014	502009	     2
502014	502022	     3
502014	502023	     4
502014	502024	     5

How do I put the Param1, Param2, Param3... in PresentOrder?

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Ordering the columns in a pivot table John Hall <foundarecord@gmail.com> - 2020-04-11 09:00 -0700
  Re: Ordering the columns in a pivot table Erland Sommarskog <esquel@sommarskog.se> - 2020-04-12 13:59 +0200

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