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Groups > microsoft.public.sqlserver.programming > #31350
| Newsgroups | microsoft.public.sqlserver.programming |
|---|---|
| Date | 2020-04-11 09:00 -0700 |
| Message-ID | <9c212941-b3a2-4f07-b29c-e8145580bbad@googlegroups.com> (permalink) |
| Subject | Ordering the columns in a pivot table |
| From | John Hall <foundarecord@gmail.com> |
I have a data table with these 3 columns
SELECT [TestID],[ParameterID],[TextValue]
FROM [ParameterEntries]
select TestID, [1] as Param1, [2] as Param2, [3] as Param3, [4] as Param4, [5] as Param5
from (select TestID, TextValue,
row_number() over(partition by TestID order by ParameterID) rnk
from ParameterEntries WHERE TestID = (SELECT TOP 1 TestID FROM Subgroups WHERE CharID = 502107)
) p
pivot(max(TextValue) for rnk in ([1], [2], [3], [4], [5])) piv
TestID Param1 Param2 Param3 Param4 Param5
502014 20147338 3w 2.14 1.49 1.73
SELECT [PartID], [ParameterID], [PresentOrder]
FROM [ParametersUsed]
WHERE PartID = (SELECT PartID FROM CharList WHERE CharID = 502107)
ORDER BY PresentOrder
TestID ParameterID PresentOrder
502014 154 1
502014 502009 2
502014 502022 3
502014 502023 4
502014 502024 5
How do I put the Param1, Param2, Param3... in PresentOrder?
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Ordering the columns in a pivot table John Hall <foundarecord@gmail.com> - 2020-04-11 09:00 -0700 Re: Ordering the columns in a pivot table Erland Sommarskog <esquel@sommarskog.se> - 2020-04-12 13:59 +0200
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