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Date: Sat, 11 Apr 2020 09:00:59 -0700 (PDT)
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Subject: Ordering the columns in a pivot table
From: John Hall <foundarecord@gmail.com>
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Xref: csiph.com microsoft.public.sqlserver.programming:31350

I have a data table with these 3 columns 
SELECT [TestID],[ParameterID],[TextValue]
  FROM [ParameterEntries]

select TestID, [1] as Param1, [2] as Param2, [3] as Param3, [4] as Param4, [5] as Param5
from (select TestID, TextValue,
    row_number() over(partition by TestID order by ParameterID) rnk
  from ParameterEntries WHERE TestID = (SELECT TOP 1 TestID FROM Subgroups WHERE CharID = 502107)
) p
pivot(max(TextValue) for rnk in ([1], [2], [3], [4], [5])) piv

TestID  Param1          Param2  Param3  Param4  Param5
502014	20147338	3w	2.14	1.49	1.73

SELECT [PartID], [ParameterID], [PresentOrder]
  FROM [ParametersUsed]
  WHERE PartID = (SELECT PartID FROM CharList WHERE CharID = 502107)
  ORDER BY PresentOrder

TestID  ParameterID  PresentOrder
502014	154	     1
502014	502009	     2
502014	502022	     3
502014	502023	     4
502014	502024	     5

How do I put the Param1, Param2, Param3... in PresentOrder?