declare -f produces non eval'able output

From	isabella parakiss <izaberina@gmail.com>
Newsgroups	gnu.bash.bug
Subject	declare -f produces non eval'able output
Date	2015-08-13 18:06 +0200
Message-ID	<mailman.8264.1439482071.904.bug-bash@gnu.org> (permalink)

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declare -f doesn't know that most keywords are valid function names:

$ function time () { :; }
$ declare -f time
time () 
{ 
    :
}

It should probably check if the name is if/for/time... before printing it.


---
xoxo iza

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declare -f produces non eval'able output isabella parakiss <izaberina@gmail.com> - 2015-08-13 18:06 +0200

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